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3 years ago

Compare and contrast the properties of charcoal and carbon dioxide

2 answers:

4 0

Carbon and Oxygen both are on the second period, therefore, they both have two energy shells.- Carbon's atomic number is 6, and Oxygen's atomic number is 8. So Carbon has 6 protons and electrons, and Oxygen has 8 protons and electrons.- Carbon's atomic mass (or mass number) is 12, and Oxygen's atomic mass is 16.- Carbon has 6 neutrons, and Oxygen has 8 neutrons.- Carbon can be black, while Oxygen is clear and odorless.

SpyIntel [72]3 years ago

3 0

Answer:

Carbon dioxide is a gas that is invisible. It plays a significant role by being one of the most effective green house gas. Earth's atmosphere is comprised of about 0.03% of Carbon dioxide (CO₂) and a small increase in this concentration can lead to an adverse effect, thereby causing global warming.

Whereas, charcoal is a dark grayish colored residual product of carbon which is obtained after the withdrawing the water and volatile components of organisms as well as plant materials. Burning of charcoal produces carbon dioxide. It is used for various purposes such as cooking fuel, industrial fuel, skin care as well as whitening of teeth.

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Why was Chernobyl built? I don't need to know what happened, I just need to know WHY it was built.

alukav5142 [94]

Answer:

It was built to house the employees of the Chernobyl Nuclear Power Plants located 4 kilometers away and became the ninth nuclear city in the Soviet Union.

Explanation:

3 0

3 years ago

Read 2 more answers

Air bags are activated when a severe impact causes a steel ball to compress a spring and electrically ignite a detonator cap. Th

Sedaia [141]

Answer:

154 g

Explanation:

Step 1: Write the balanced decomposition equation

2 NaN₃(s) ⇒ 2 Na(s) + 3 N₂(g)

Step 2: Calculate the moles corresponding to 79.5 L of N₂ at STP

At STP, 1 mole of N₂ occupies 22.4 L.

79.5 L × 1 mol/22.4 L = 3.55 mol

Step 3: Calculate the number of moles of NaN₃ needed to form 3.55 moles of N₂

The molar ratio of NaN₃ to N₂ is 2:3. The moles of NaN₃ needed are 2/3 × 3.55 mol = 2.37 mol.

Step 4: Calculate the mass corresponding to 2.37 moles of NaN₃

The molar mass of NaN₃ is 65.01 g/mol.

2.37 mol × 65.01 g/mol = 154 g

6 0

3 years ago

Find the initial temperature of 45.0g of water if its final Temperature after submerging a metal with the mass of 8.5g is 22.0°C

Korolek [52]

The initial temperature of the water that resulted in the final temperature of the water-metal mixture is 20.7 ⁰C.

"Your question is not complete, it seems to be missing the following information;"

the specific heat capacity of the metal is 0.45 J/g⁰C.

The given parameters;

mass of water, $m_w$ = 45 g
final temperature of the water, $t_w$ = 22 ⁰C
mass of the metal, m = 8.5 g
initial temperature of the metal, t = 82 ⁰C.
specific heat capacity of the metal, c = 0.45 J/g⁰C.

The initial temperature of the water will be calculated by applying the principle of conservation of energy;

heat gained by water = heat lost by metal

$Q_{water} = Q_{metal}$

$m_wc_w \Delta t_w = mc\Delta t$

where;

$c_w$ is the specific heat capacity of the water = 4.184 J/g⁰C.

Substitute the given values;

45 x 4.184 x (22 - t) = 8.5 x 0.45 x (85 - 22)

4142.16 - 188.28t = 240.98

188.28t = 4142.16 - 240.98

188.28t = 3901.18

$t = \frac{3901.18}{188.28} \\\\t = 20.7 \ ^0 C$

Thus, the initial temperature of the water that resulted in the final temperature of the water-metal mixture is 20.7 ⁰C.

Learn more here:brainly.com/question/15345295

8 0

3 years ago

Krypton gas is 21 times denser than helium gas at the same temperature and pressure. which gas is predicted to effuse faster

Inessa [10]

Helium gas would be the one to effuse faster as compared to krypton. This is because krypton is heavier than helium. Heavier molecules would require more energy to move so they tend to effuse slower than molecules that are lighter which will only require less energy.

7 0

3 years ago

A 10.0 mL sample of 0.75 M CH3CH2COOH(aq) is titrated with 0.30 M NaOH(aq) (adding NaOH to CH3CH2COOH). Determine which region o

Llana [10]

Answer:

5.75

Explanation:

Weak acid and strong base,

Make it a two part problem

The first will be Partial neutralization of the weak acid, while the second is the equilibrium and final pH

1.Parameters

HC2H3O2 =10mL x 0.75M = 7.5 mmol

NaOH =22mL x 0.30M = 6.6 mmol

R HC2H3O2 + OH- --> C2H3O2- + H2O

I 7.5 mmol 6.6 mmol 0 mmol ignore

C -6.6 mmol -6.6 mmol +6.6 mmol

E 0.9 mmol 0.0 mmol 6.6 mmol

2.) HC2H3O2 --> H+ + C2H3O2-

Initial concentrations

[HC2H3O2]: 0.9 mmol / 32mL = 0.0281M

[H+]:

[C2H3O2-]: 6.6 mmol x 32mL = 0.206M

Concentrations at equilibrium

[HC2H3O2]: 0.0281M - x

[H+]: [C2H3O2-]: 0.206M + x

If x is small and can be ignored except [H+]

Substitute and solve

1.3 x 10-5 = (x)(0.206)

(0.0281)

X= 1.77 x 10-6M => pH = 5.75

3 0

3 years ago