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AveGali [126]
3 years ago
5

Air bags are activated when a severe impact causes a steel ball to compress a spring and electrically ignite a detonator cap. Th

is causes sodium azide (NaN3) to decompose explosively according to the following reaction. 2 NaN3(s) --> 2 Na(s) 3 N2(g) What mass in grams of NaN3(s) must be reacted in order to inflate an air bag to 79.5 L at STP
Chemistry
1 answer:
Sedaia [141]3 years ago
6 0

Answer:

154 g

Explanation:

Step 1: Write the balanced decomposition equation

2 NaN₃(s) ⇒ 2 Na(s) + 3 N₂(g)

Step 2: Calculate the moles corresponding to 79.5 L of N₂ at STP

At STP, 1 mole of N₂ occupies 22.4 L.

79.5 L × 1 mol/22.4 L = 3.55 mol

Step 3: Calculate the number of moles of NaN₃ needed to form 3.55 moles of N₂

The molar ratio of NaN₃ to N₂ is 2:3. The moles of NaN₃ needed are 2/3 × 3.55 mol = 2.37 mol.

Step 4: Calculate the mass corresponding to 2.37 moles of NaN₃

The molar mass of NaN₃ is 65.01 g/mol.

2.37 mol × 65.01 g/mol = 154 g

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Answer:

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40 N.

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3 years ago
A cylindrical glass tube 12.7 cm in length is filled with mercury (density =13.6 g/mL). The mass of mercury needed to fill the t
Kay [80]

Answer:

The inner diameter of the tube is 0.4410 cm.

Explanation:

Height upto which mercury is filled = 12.7 cm

Mass of mercury = 105.5 g

Density of mercury = 13.6 g/mL =13.6 g/cm^3

Volume of mercury:

\frac{Mass}{Density}=\frac{105.5 g}{13.6 g/cm^3}=7.7573 cm^3

A mercury in cylindrical glass tube is at height of 12.7 cm.

The radius of the inner diameter of the glass tube = r

Volume of cylinder = \pi r^2h

7.7573 cm^3=3.14\times r^2\times 12.7 cm

r = 0.4410 cm.

7 0
3 years ago
Classify each of the following equations as synthesis, decomposition, or replacement.
Sonja [21]

Answer: A. Is decomposition

B. Is synthesis where Na combines with Cl to form NaCl

C. Is single displacement or replacement. Mg displaces Cu.

Explanation:

7 0
3 years ago
The equilibrium constant, Kp, for the reaction H2(g) + I2(g) → 2HI(g) is 55.2 at 425°C. A rigid cylinder at that temperature con
Fiesta28 [93]

<u>Answer:</u> No, the reverse reaction must proceed to establish equilibrium.

<u>Explanation:</u>

K_p is the constant of a certain reaction at equilibrium while Q_p is the quotient of activities of products and reactants at any stage other than equilibrium of a reaction.

For the given chemical reaction:

H_2(g)+I_2(g)\rightleftharpoons 2HI(g)

The expression of Q_p for above equation follows:

Q_p=\frac{(p_{HI})^2}{p_{H_2}\times p_{I_2}}

We are given:

p_{HI}=1.055atm\\p_{H_2}=0.127atm\\p_{I_2}=0.134atm

Putting values in above equation, we get:

Q_p=\frac{(1.055)^2}{0.127\times 0.134}=65.41

We are given:

K_p=55.2

There are 3 conditions:

  • When K_{p}>Q_p; the reaction is product favored.
  • When K_{p}; the reaction is reactant favored.
  • When K_{p}=Q_p; the reaction is in equilibrium.

As, Q_p>K_p, the reaction will be favoring reactant side or the reaction must proceed in the reverse direction.

Hence, no, the reverse reaction must proceed to establish equilibrium.

6 0
3 years ago
What is the Percent yield is 4.65 got copper is produced by 1.87 percent yield is got copper is produced when 1.87 grams of alum
konstantin123 [22]

Answer:

The percent yield is 70.486%

Explanation:

3CuSO_{4}+2Al\longrightarrow Al_{2}(SO_{4})_{3}+3Cu\\\\Weight\:of\:Al=1.87g\\54g\:of\:Al\:will\:give\:190.5g\:of\:Cu\\

1.87g\:of\:Al\:gives=\frac{190.5\times1.87}{54}=6.597g\:of\:Cu\\ \\Weight\:of\:Cu\:obtained=4.65g\\Theoretical\:Yield=6.597g\\Experimental\:Yield=4.65g\\Percent\:Yield=\frac{Experimental\:Yield}{Theoretical\:Yield}\times100=\frac{4.65}{6.597}\times100=70.486\%

Hence, the percent yield is 70.486%

7 0
4 years ago
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