Answer:
I looked it up so the answer is for sure A
Explanation:
Your answer would be D you welcome !
I’m not too sure, but I think it was element Cerium :)
Answer:
C4H8
Explanation:
M(CF2) = M(C) + 2M(F) = 12.0 + 2*19.0 = 50.0 g/mol
M(unknown)/M(CF2) = 200.4 g/mol /50.0 g/mol = 4
So we need to take CF2 4 times.
C4H8
Answer:
The answer to your question is: Oxidation number is III,
formula Cr₂(SO₄)₃
Explanation:
Data
Chromium (III) sulfate
Oxidation state of Cr = ?
Chemical formula
Process
The oxidation number of Chromium is given in roman numerals, then the oxidation number is III.
Chemical formula Cr₂(SO₄)₃