We are given the equation:
F = 2.25+0.2(m-1)
where:
F is the fare
m is the number of miles.
In question 7, we are given that the fare (F) is equal to $6.05 and we need to get the number of miles. To do so, we will simply substitute with the fare in the given equation and solve for the number of miles (m) as follows:
F = 2.25 + 0.2(m-1)
6.05 = 2.25 + 0.2(m-1)
6.05-2.25 = 0.2(m-1)
3.8 = 0.2(m-1)
3.8/0.2 = m-1
19 = m-1
m = 19+1
m = 20 miles
Number 8 is exactly the same, but we will substitute F=7.65 and again solve for m
Answer:
The Total amount of of 33 boxes of chocolates including taxes is $838.358
Step-by-step explanation:
Given as :
The sales tax rate for city = 4.306%
The sales tax rate for the state = 44%
Total number of boxes = 33
The price of each chocolates = $17.13
So , The price of 33 boxes of chocolates = $17.13 × 33
I.e The price of 33 boxes of chocolates = $565.29
Now total tax including state and city = 4.306% + 44% = 48.306 %
So, The tax amount paid for 33 boxes of chocolates = 48.306 % of $565.29
∴ The tax amount paid for 33 boxes of chocolates = 48.306 % × $565.29
= 0.48306× $565.29
= $273.068
∴ The Total amount of of 33 boxes of chocolates including taxes = $565.29 + $273.068 = $838.358
Hence The Total amount of of 33 boxes of chocolates including taxes is $838.358 . Answer
∫ √(4x - x²) dx
= 2[(4x - x²)^(3/2)] / 3(4 - 2x)
<h3>Answer is -9</h3>
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Work Shown:
(g°h)(x) is the same as g(h(x))
So, (g°h)(0) = g(h(0))
Effectively h(x) is the input to g(x). Let's first find h(0)
h(x) = x^2+3
h(0) = 0^2+3
h(0) = 3
So g(h(x)) becomes g(h(0)) after we replace x with 0, then it updates to g(3) when we replace h(0) with 3.
Now let's find g(3)
g(x) = -3x
g(3) = -3*3
g(3) = -9
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alternatively, you can plug h(x) algebraically into the g(x) function
g(x) = -3x
g( h(x) ) = -3*( h(x) ) ... replace all x terms with h(x)
g( h(x) ) = -3*(x^2 + 3) ... replace h(x) on right side with x^2+3
g( h(x) ) = -3x^2 - 9
Next we can plug in x = 0
g( h(0) ) = -3(0)^2 - 9
g( h(0) ) = -9
we get the same result.
