You have two angles congruent, plus a side that's NOT between them.
I guess you'd call that situation " AAS " for "angle-angle-side".
That's what you have, and it's NOT enough to prove the triangles
congruent. There can be many many different pairs of triangles
that have AAS = AAS.
So there's no congruence postulate to cover this case, because they're
not necessarily.
Answer:
angle Z=20°
side xy≈15.36
hypotenuse≈19.49
Step-by-step explanation:
Find angle z adding the other two angles and subtracting that by 180 to get 20.
(12)tan(20) gets you side xy which is 15.36
12^2+15.36^2=xz^2
Answer:
Area of parallelogram= base × perpendicular height
base= 20cm height= 13
Area= 20cm×13cm
Area= 260cm²
Therefore the area of the parallelogram is 260cm²
