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77julia77 [94]
1 year ago
10

Draw cross diagram showing formation of Calcium Chloride

Chemistry
1 answer:
Zarrin [17]1 year ago
7 0

Explanation:

First I'm going to draw the structure of the neutral calcium atom and the structure of the chlorine atom.

Now I'm going to draw only the valence shells of ions that participate in ionic bonding:

So Ca2+ will donate 2 electrons for both 2 atoms of Chlorine, forming CaCl2.

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Which line segment on the graph represents boiling
hoa [83]
1. There is no graph given

2. ENERGY LEVELS!!!

Boiling is the process of liquid(middle energy, flat line) turning into a gas(lots of energy, flat line), hope this helps
8 0
4 years ago
Any two substances which are odourless​
STatiana [176]

Answer:

This question perplexes me somewhat. If we as humans are not able to detect a scent or odor from certain substances, that does not of necessity mean those substances are not giving off an odor, and are therefore not “truly” odorless, just odorless to the less sensitive noses of humans.

Water is supposedly odorless, but I know quite well of a test where subjects did a blind tasting, only instead of wine these people were tasting Australian waters, sourced from different locations around the country.

All of these tasters (professionals) were able to differentiate the waters and from what I recall, were all accurate. These wine buffs use their palates as well as their taste-buds, so, were there no odor, their task would have had a greater degree of difficulty.

My own baby sister has such a sensitive palate that she can tell you if you serve her a glass of water from the fridge whether that water was fresh, straight from the tap (unfiltered), filtered or had been boiled before and whether it had been boiled for more than five minutes or not. Truly.

So I would find it difficult to answer your question, “What substances are truly odorless?” , because I am not sure of the criteria you mean by “truly” odorless. In other words, If you are talking about zero degrees, are you talking of the freezing point of water, absolute zero or zero degrees Kelvin?

I’m sure there are substances that are odorless, to humans, but are those same substances “truly” odorless, or only to our perception of them?

Hope this helps, have a wonderful day/night, and stay safe!

8 0
3 years ago
Recovery standards are a necessary tool for determining exactly how much of a particular analyte you are able to extract from a
Dafna11 [192]

Answer:

2.05mg Fe/ g sample

Explanation:

In all chemical extractions you lose analyte. Recovery standards are a way to know how many analyte you lose.

In the problem you recover 3.5mg Fe / 1.0101g sample: <em>3.465mg Fe / g sample. </em>As real concentration of the standard is 4.0 mg / g of sample the percent of recovery extraction is:

3.465 / 4×100 = <em>86,6%</em>

As the recovery of your sample was 1.7mg Fe / 0.9582g, the Iron present in your sample is:

1.7mg Fe / 0.9582g sample× (100/86.6) = <em>2.05mg Fe / g sample</em>

<em></em>

I hope it helps!

5 0
4 years ago
The subgroup that comes after genus is-
lana [24]
C)  family
The subgroup that comes after genus is
5 0
4 years ago
Read 2 more answers
A student dissolves of 15 g aniline in of a solvent with a density of . The student notices that the volume of the solvent does
VikaD [51]

The given question is incomplete. The complete question is ;

A student dissolves of 15 g aniline in 200 ml of a solvent with a density of 1.05 g/ml. The student notices that the volume of the solvent does not change when the aniline dissolves in it. Calculate the molarity and molality of the student's solution. Be sure each of your answer entries has the correct number of significant digits.

Answer: The molarity is 0.81 M and molality is 0.82 m

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute  

V_s = volume of solution in ml = 200 ml

{\text {moles of solute}=\frac{\text {given mass}}{\text {molar mass}}=\frac{15g}{93g/mol}=0.16mol

Now put all the given values in the formula of molarity, we get

Molarity=\frac{0.16\times 1000}{200}=0.81M

Thus molarity is 0.81 M

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

Molarity=\frac{n\times 1000}{W_s}

where,

n = moles of solute

W_s = weight of solvent in g

{\text {moles of solute}=\frac{\text {given mass}}{\text {molar mass}}=\frac{15g}{93g/mol}=0.16mol

Mass of solution = Density\times Volume=1.05g/ml\times 200ml=210g

mass of solvent = mass of solution - mass of solute = (210 - 15) g = 195 g

Now put all the given values in the formula of molality, we get

Molality=\frac{0.16\times 1000}{195g}=0.82mole/kg

Therefore, the molality of solution is 0.82m

3 0
3 years ago
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