Two basic ways in which to do this problem:
1. Find and apply the LCD.
2. Convert all of the given numbers to their decimal form, to 2 or 3 places only.
Try #2 first:
5/6 = 0.83
4/5 = 0.80 is not between 5/6 and 1. Reject it.
4/7 = 0.57 Reject
6/7 = 0.86 This is between 5/6 and1. This is the answer.
Step-by-step explanation:
yan po ang sagot ko dahil yan po ang pagkakaintindi ko
The answer to your is 100 volts
Answer: D. The probability of a time from 75 seconds to 250 seconds.
Step-by-step explanation:
We know that a density curve graph for all of the possible values from a to b can be used to find the the probability of the values from a to b .
Given: A density graph for all of the possible times from 50 seconds to 300 seconds.
Then it can be used to find the the probability of a time in the range from 50 seconds to 300 seconds.
From all the given option only option D gives the interval which is lies in the above range.
i.e A density graph for all of the possible times from 50 seconds to 300 seconds can be used to determine the probability of a time from 75 seconds to 250 seconds.
an=a1+d(n−1) is the explicit and a recursive formula for each sequence .
<h3>What is sequence?</h3>
See the pattern
-32-(-20) = -12
-20-(-8) = -12
-8-4 = -12
By this the explicit and a recursive formula for each sequence is an=a1+d(n−1).
An ordered group of numbers with a shared difference between each succeeding word is known as an arithmetic sequence. For instance, the common difference in the arithmetic series 3, 9, 15, 21, and 27 is 6.
Arithmetic sequences are sequences containing these patterns. The distance between succeeding terms in an arithmetic series is always the same. The difference between consecutive words is always two, hence the sequence 3, 5, 7, 9... is arithmetic.
An explicit formula that states a = d (n - 1) + c, where d is the common difference between succeeding words, and c = a1, can be used to establish an arithmetic sequence.
To learn more about arithmetic sequence from the given link:
brainly.com/question/15412619
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