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Xelga [282]
3 years ago
8

The formula y equals 15 left parenthesis 1.26 right parenthesis to the power of x gives the number of cellular phone users y (in

millions) in some country for the years 1994 through 2006. In this formula, x = 0 corresponds to 1994, x = 1 corresponds to 1995, and so on. Use this model to predict the number of cellular phone users in the year 2006.
The predicted number of cellular phone users in the year 2006 is __________ million. (Round to the nearest whole number as needed.)
Mathematics
1 answer:
Alexus [3.1K]3 years ago
7 0

Answer:

2.3 billion

Step-by-step explanation:

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Simplify 3a+2ab-6a+2b-ab
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3a + 2ab - 6 + 2b - ab

First, gather like terms. / Your problem should look like: (3a - 6a) + (2ab - ab) + 2b
Second, simplify. / Your problem should look like: -3a + ab + 2b

Answer: -3a + ab + 2b

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4 years ago
Convert the numeral to a numeral in base ten. 2331nine
BaLLatris [955]

Answer:

Step-by-step explanation:

Converting 2331 to base 10.

2*93=1458

3*92=243

3*91=27

1*90=1

Adding all to get Ans=172910

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4 years ago
Please help and thank you
Sauron [17]

Answer: c

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ValentinkaMS [17]

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3 years ago
Read 2 more answers
A ball is thrown into the air and its position is given by h ( t ) = − 6.3 t 2 + 53 t + 24 where h is the height of the ball in
nordsb [41]

Answer:

h'(t) = -12.6 t +53

Now we can set up the derivate equal to 0 and we have:

-12.6 t +53 = 0

And solving for t we got:

t = \frac{53}{12.6}= 4.206

For the second derivate respect the time we got:

h''(t) = -12.6

So then we can conclude that t = 4.206 is a maximum for the function.

And the corresponding height would be:

h(t=4.206) = -6.3(4.206)^2 +53*4.206+24= 135.468 ft

So the maximum occurs at t = 4.206 s and with a height of 135.468 m

Step-by-step explanation:

For this case we have the following function:

h(t) = -6.3t^2 +53 t+24

In order to maximize this function we need to take the first derivate respect the time and we have:

h'(t) = -12.6 t +53

Now we can set up the derivate equal to 0 and we have:

-12.6 t +53 = 0

And solving for t we got:

t = \frac{53}{12.6}= 4.206

For the second derivate respect the time we got:

h''(t) = -12.6

So then we can conclude that t = 4.206 is a maximum for the function.

And the corresponding height would be:

h(t=4.206) = -6.3(4.206)^2 +53*4.206+24= 135.468 ft

So the maximum occurs at t = 4.206 s and with a height of 135.468 m

8 0
4 years ago
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