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3 years ago

Pls help its a optional math question

Mathematics

1 answer:

Pepsi [2]3 years ago

6 0

Answer:

70cm

Step-by-step explanation:

33=27/360*2*22/7*r

33*2520/1188=r

83160/1188=r

r=70cm

hope it's right

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Can someone please help me and explain? please

mariarad [96]

Composite figure is made up of 4 triangles and a square.

Area of Square = Length x Length
Area of Square = 12 x 12
Area of Square= 144 cm²

Area of triangle = 1/2 x base x height
Area of triangle = 1/2 x 12 x 8
Area of triangle = 48 cm²

Area of 4 Triangles = 48 x 4
Area of 4 Triangles = 192 cm²

Total Area = 144 + 192 = 336 cm²

$\Longrightarrow \boxed { \boxed { Answer : 336 cm^{2} }}$

4 0

3 years ago

PLEASE HELP OUT!!! im super lost.

Alex73 [517]

Just replace X with the given value.

X = -3

f(-3) = 5 - (-3)

f(-3) = 5 +3

f(-3) = 8

3 0

3 years ago

Idk if my answer is right pls help will give like and brainliest

Arlecino [84]

Answer:

Yes that would be correct!

Step-by-step explanation:

You need 5a and 34 are needed in the equation and so is the x symbol

6 0

3 years ago

Read 2 more answers

1. Jay said, “The amount of money in my checking account is less than $50.00, but greater than $40.00.” Which statements about t

Pepsi [2]

I don't know the options but I guess it would be something like this:
40,000 < x < 50,000

4 0

3 years ago

the first group of students consists of 10 and their average age was 13 years old the next group consisted of 30 students and th

Kazeer [188]

Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : $\text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}$

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. $13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130$ (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. $9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270$ (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

Combined students of both groups (first and next group )= 10+30=40

Now , the average of both groups = $\dfrac{\text{Sum of combined students}}{\text{combined students}}$

$=\dfrac{400}{40}=10$

Hence, the average was 9 years old find the average age of both groups is 10 years old.

4 0

3 years ago