You would first have to find the area of the other part.
<span>Let r(x,y) = (x, y, 9 - x^2 - y^2)
So, dr/dx x dr/dy = (2x, 2y, 1)
So, integral(S) F * dS
= integral(x in [0,1], y in [0,1]) (xy, y(9 - x^2 - y^2), x(9 - x^2 - y^2)) * (2x, 2y, 1) dy dx
= integral(x in [0,1], y in [0,1]) (2x^2y + 18y^2 - 2x^2y^2 - 2y^4 + 9x - x^3 - xy^2) dy dx
= integral(x in [0,1]) (x^2 + 6 - 2x^2/3 - 2/5 + 9x - x^3 - x/3) dx
= integral(x in [0,1]) (28/5 + x^2/3 + 26x/3 - x^3) dx
= 28/5 + 40/9 - 1/4
= 1763/180 </span>
3(n-t) = 3n- 3t
It is you mean about ?
Alright! Given that C(x) is Cost(Students) = 558, we can eliminate:
2. 558 students paid to attend the event.
5. The event generated $124 from student revenue.
Now, in order to find the cost per student we simply divide 124 on both sides:

124 cancels on the left and 558/124 is 4.5 or $4.50.
Since we just determined the cost of one student, we can eliminate 3.
To check if 124 students paid, we simply add the cost to the equation and check:
4.5(124) = 558
558 = 558 √
It checks out, so we determined that both 1 and 4 are correct.