Correct question is;
A football is kicked up into the air. Its height, H, above the ground, in meters, at t seconds can be modelled by () = 24 − 4.9²
(a) Determine the expression for the instantaneous rate of change in height at time t.
(b) Determine ' (2) What does ' (2) represent?
Answer:
A) '() = 24 − 9.8
B) '(2) = 4.4 m/s
It means that at a distance of 2 m above the ground, the speed of the ball is 4.4 m/s
Step-by-step explanation:
We are given the function to represent the height as;
() = 24 − 4.9²
A) expression for the instantaneous rate of change in height at time t will be gotten by differentiation of the height function. Thus;
'() = 24 − 9.8
B) '(2) = 24 - 9.8(2)
'(2) = 4.4 m/s
This means that at a distance of 2 m above the ground, the speed of the ball is 4.4 m/s
Answer:
0.08
Step-by-step explanation:
![{5}^{ - 2} \times \sqrt[3]{8} \\ \\ = {5}^{ - 2} \times \sqrt[3]{ {2}^{3} } \\ \\ = \frac{1}{ {5}^{2} } \times 2 \\ \\ = \frac{1}{25} \times 2 \\ \\ = \frac{2}{25} \\ \\ =0.08](https://tex.z-dn.net/?f=%20%7B5%7D%5E%7B%20-%202%7D%20%20%5Ctimes%20%20%5Csqrt%5B3%5D%7B8%7D%20%20%5C%5C%20%20%5C%5C%20%20%3D%20%20%7B5%7D%5E%7B%20-%202%7D%20%20%5Ctimes%20%20%5Csqrt%5B3%5D%7B%20%7B2%7D%5E%7B3%7D%20%7D%20%20%5C%5C%20%20%5C%5C%20%20%3D%20%20%5Cfrac%7B1%7D%7B%20%7B5%7D%5E%7B2%7D%20%7D%20%20%5Ctimes%202%20%5C%5C%20%20%5C%5C%20%20%20%3D%20%5Cfrac%7B1%7D%7B25%7D%20%20%5Ctimes%202%20%5C%5C%20%20%5C%5C%20%20%3D%20%20%5Cfrac%7B2%7D%7B25%7D%20%5C%5C%20%5C%5C%20%3D0.08)
The answer is B.) F and I
Answer:
252
Step-by-step explanation:
<u>Prime factors of 46656:</u>
<u>Possible values of x:</u>
- (2*3)³= 216
- 3³ = 27
- 2³ = 8
- 1
<u>Sum of them:</u>
