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Alecsey [184]
3 years ago
10

How many g of zinc are required to produced 50g of hydrogen when reacting zinc with sulphuric acid?

Chemistry
2 answers:
elena-s [515]3 years ago
6 0

Answer:

1621.53 g Zn.

Explanation:

The balanced equation is:

Zn + H2SO4  --->  ZnSO4 + H2.

So, using the molar masses of Zn and H2:

65.38 g of Zn produces 2*1.008 = 2.016 g H2.

Thus 2.016 g of H2 is produced from 65.38 g Zn.

and 50g H2 is produced from   (50 * 65.38) / 2.016 g

= 1621.53 g Zn.

zheka24 [161]3 years ago
5 0

Answer: 1618.8g of Zinc

Explanation:

We begin by writing a balanced chemical equation for the reaction.

Zn (s) + H2SO4 (aq)  ---------->  ZnSO4 (aq)  + H2 (g)

Atomic mass of Zinc is 65.4g/mol

Molecular mass of hydrogen gas is 2.02 g/mol

Looking at the balanced equation;

2.02g is produced by  65.4g of Zn

    50g would be produced by  65.4÷ 2.02 x  50 = 1618.8g of Zinc

                                                 

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