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IrinaVladis [17]
3 years ago
13

What amount of moles does 60.5 L of carbon dioxide occupy at 2.15 atm and 25 degrees C?

Chemistry
1 answer:
xeze [42]3 years ago
8 0

Answer: 5.3 moles

Explanation:

Hi, to answer this question we have to apply the next formula:

n = PV/RT

Where:

n = number of moles

P= Pressure = 2.15 atm

V= volume = 60.5 L

R = 0.0821 atm(L)/mol(K)

T = temperature = 25 °+ 273.15 = 298.15 Kelvin  

Replacing with the values given:

n = 2.15 (60.5) / 0.0821 (298.15) = 5.3 moles.

Feel free to ask for more if needed or if you did not understand something.

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Use the balanced equation given below to solve the following problem; Calculate the volume in liters of CO produced by the react
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Answer: 40.3 L

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}

\text{Moles of} Sb_2O_3=\frac{175g}{291.5g/mol}=0.600moles

Sb_2O_3+3C\rightarrow 2Sb+3CO  

According to stoichiometry :

1 moles of Sb_2O_3 produces = 3 moles of CO

Thus 0.600 moles of Sb_2O_3 will produce=\frac{3}{1}\times 0.600=1.80moles  of CO

Volume of CO=moles\times {\text {Molar volume}}=1.80moles\times 22.4L/mol=40.3L

Thus 40.3 L of CO is produced.

6 0
3 years ago
What is water's density at 93 ∘C? Assume a constant coefficient of volume expansion. Express your answer with the appropriate un
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Answer:

982.5 kg/m³

Explanation:

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ρ₁ = ρ₀/(1 + β*(t₁ - t₀))

Where ρ₁ is the final density, ρ₀ the initial density, β is the constant coefficient of volume expansion, t₁ the final temperature, and t₀ the initial temperature.

At t₀ = 4°C, the water desity is ρ₀ = 1,000 kg/m³. The value of the constant for water is β = 0.0002 m³/m³ °C, so, for t₁ = 93°C

ρ₁ = 1,000/(1 + 0.0002*(93 - 4))

ρ₁ = 1,000/(1+ 0.0178)

ρ₁ = 982.5 kg/m³

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