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IrinaVladis [17]
3 years ago
13

What amount of moles does 60.5 L of carbon dioxide occupy at 2.15 atm and 25 degrees C?

Chemistry
1 answer:
xeze [42]3 years ago
8 0

Answer: 5.3 moles

Explanation:

Hi, to answer this question we have to apply the next formula:

n = PV/RT

Where:

n = number of moles

P= Pressure = 2.15 atm

V= volume = 60.5 L

R = 0.0821 atm(L)/mol(K)

T = temperature = 25 °+ 273.15 = 298.15 Kelvin  

Replacing with the values given:

n = 2.15 (60.5) / 0.0821 (298.15) = 5.3 moles.

Feel free to ask for more if needed or if you did not understand something.

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Equal masses (in grams) of hydrogen gas and oxygen gas are reacted to form water. Which substance is limiting?
Sonbull [250]

Answer:

a. Oxygen gas is limiting

Explanation:

hydrogen gas and oxygen gas are reacted to form water

2H₂ + O₂  →  2H₂O

the above balanced equation shows that 2 moles of H₂ is required for 1 mole of O₂

Given equal masses of H₂ and O₂

assuming 'x' gm for each, no. of moles of each gas  =

no. of moles of H₂ = x/2 = 0.5x moles

no.of moles of O₂ = x/32 = 0.031x moles

This shows that no. of moles of O₂ is very less so O₂ will become the limiting reagent.

3 0
3 years ago
Read 2 more answers
Thermal energy always moves from a greater energy level to a lesser energy level
Nookie1986 [14]

Answer:

\fbox{Law -Based \: on \: laws \: of \: thermodynamic}

Explanation:

At constant pressure Thermal energy always moves from a greater energy level to a lesser energy level, laws of thermodynamics prove that.

Nature always likes to attain equilibrium either it's movement of heat energy or flow of water from higher region to lower region. The first and second law of thermodynamics are profe of that, the first law says that the total energy of universe is Constant. Energy can not be destroyed it always changes from one form to another, by work and heat. The second law explains why thermal energy moves from a greater energy level to a lesser energy level, it deals with the change in entropy of a system and surrounding and states heat flows from hot environment to cold environment.

<em><u>Thanks for joining brainly community!</u></em>

6 0
2 years ago
Are your knees the elbows of your legs or are your elbows the knees of your
Nimfa-mama [501]

Answer:

hi

Explanation:

it is confusing lol

but i think that it is C.both

hope it helps

have a nice day

5 0
2 years ago
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___CH4 + ___O2 → ___CO2 + ___H2O
DaniilM [7]
CH4 + 2O2 =======> CO2 + 2H2O
5 0
3 years ago
Design a test to determine whether thorium-234 also emits particles. First, explain how Rutherford’s experiment measured positiv
liubo4ka [24]

The characteristics of the α and β particles allow to find  the design of an experiment to measure the ²³⁴Th particles is:

  • On a screen, measure the emission as a function of distance and when the value reaches a constant, there is the beta particle emission from ²³⁴Th.
  • The neutrons cannot be detected in this experiment because they have no electrical charge.

In Rutherford's experiment, the positive particles directed to the gold film were measured on a phosphorescent screen that with each arriving particle a luminous point is seen.

The particles in this experiment are α particles that have two positive charge and two no charged is a helium nucleus.

The test that can be carried out is to place a small ours of Thorium in front of a phosphorescent screen and see if it has flashes, with the amount of them we can determine the amount of particle emitted per unit of time.

Thorium has several isotopes, with different rates and types of emission:

  • ²³²Th emits α particles, it is the most abundant 99.9%
  • ²³⁴Th emits β particles, exists in small traces.

In this case they indicate that the material used is ²³⁴Th, which emits β particles that are electrons, the detection of these particles is more difficult since it has one negative charge, it has much lower mass, but they can travel further than the particles α, therefore, for what type of isotope we have, we can start measuring at a small distance and increase the distance until the reading is constant. At this point all the particles that arrive are β, which correspond to ²³⁴Th.

Neutron detection is much more difficult since these particles have no charge and therefore do not interact with electrons and no flashing on the screen is varied.

In conclusion with the characteristics of the α and β particles we can find the design of an experiment to measure the ²³⁴Th particles is:

  • On a screen, measure the emission as a function of distance and when the value reaches a constant, there is the β particle emission from ²³⁴Th.
  • The neutrons cannot be detected in this experiment because they have no electrical charge.

Learn more about radioactive emission here: brainly.com/question/15176980

7 0
2 years ago
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