What amount of moles does 60.5 L of carbon dioxide occupy at 2.15 atm and 25 degrees C?
1 answer:
Answer: 5.3 moles
Explanation:
Hi, to answer this question we have to apply the next formula:
n = PV/RT
Where:
n = number of moles
P= Pressure = 2.15 atm
V= volume = 60.5 L
R = 0.0821 atm(L)/mol(K)
T = temperature = 25 °+ 273.15 = 298.15 Kelvin
Replacing with the values given:
n = 2.15 (60.5) / 0.0821 (298.15) = 5.3 moles.
Feel free to ask for more if needed or if you did not understand something.
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