Answer:
0.0991 M
Explanation:
Step 1: Write the neutralization reaction between oxalic acid and sodium hydroxide.
H₂C₂O₄ + 2 NaOH = Na₂C₂O₄ + 2 H₂O
Step 2: Calculate the moles of oxalic acid
The molar mass of H₂C₂O₄ is 90.03 g/mol. The moles corresponding to 153 mg (0.153 g) are:
Step 3: Calculate the moles of sodium hydroxide
The molar ratio of H₂C₂O₄ to NaOH is 1:2.
Step 4: Calculate the molarity of sodium hydroxide
Answer : 0.125 M
Explanation : The definition of osmotic pressure is "<span><em>the pressure can be applied on a pure solvent to prevent it passing into a given solution by osmosis</em>".
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So according to this definition, osmotic pressure can be called as directly proportional to the concentration of the solution and hence the pressure can also be directly proportional to the concentration.
Hence, if pressure is getting decreased from 28 to 7 it means it got decreased by 4 times;
28 / 7 = 4 that means;
So the concentration will be also decreased by 4 times so, 0.50 / 4 = 0.125 M
<u>0.12 atm</u><u> </u><u>vapor pressure</u><u> of ethanol at 45.0 C.</u>
What is vapor pressure in science definition?
- Vapour pressure is a measure of the tendency of a material to change into the gaseous or vapour state, and it increases with temperature.
- The temperature at which the vapour pressure at the surface of a liquid becomes equal to the pressure exerted by the surroundings is called the boiling point of the liquid.
We will use the Clausius-Clapeyron equation,
ln(P2/P1) = dHvap/R[1/T1-1/T2]
where,
P1 = unknown
P2 = 1 atm
T1 = 30 oC = 30 + 273 = 303 K
T2 = 78.3 oC = 78.3 + 273 = 351.3 K
dHvap = 39.3 kJ/mol = 39300 J/mol
R = 8.314 J/K.mol
Feed values,
ln(1/P1) = 39300/8.314[1/303 - 1/351.3]
P1 = 0.12 atm
thus, the vapor pressure at 30° C is 0.12 atm.
Learn more about vapor pressure
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Answer:
i think that the answer is that it would decrease
Explanation:
hope this helps
sorry if the answer is wrong
