Answer:
They're called Jovian planets
<u>Answer:</u>
The freezing point of a 1.7 mole aqueous ethylene glycol solution is 3.2°C
<u>Explanation:</u>
Moles present in aqueous ethylene glycol solution= m=1.7
Depression constant for water = = 1.8 deg C/m
According to formula
=1.8* 1.7
=3.2
Hence the freezing point of aqueous ethylene glycol solution is 3.2°C
Put in the values into density formula, convert cm^3 to ft^3 and write final solution.
The molecules of a solid is compactly arranged. It is made up of repeating blocks called unit cells. The density of a unit cell is:
ρ = nA/VNₐ
where
n is the number of atoms per unit cell
A is the atomic weight of solid
V is the volume of unit cell
Na is Avogadro's number (6.022×10²³)
For a face-centered cubic unit cell, there are 4 atoms (n=4). The volume of the unit cell follows the formula of the cube, s³. The atomic weight of gold is 197 g. So, the solution is as follows:
ρ = (4 atoms)(197 g/mol)(1 kg/1000 g)/(407×10⁻¹² m)³(6.022×10²³ atoms/mol)
ρ = 19,408.5 kg/m³