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2 years ago

When comparing Potassium (K) and Calcium (Ca) you must compare?

1 answer:

8 0

Vitamin K and potassium are essential micronutrients the body needs to develop and function properly. The two share some things in common, but they’re not the same.

Each has a unique set of properties and purposes. Unlike vitamin K, potassium is not a vitamin. Rather, it’s a mineral.

On the periodic table, the chemical symbol for potassium is the letter K. Thus, people sometimes confuse potassium with vitamin K.

This article highlights some of the main similarities and differences between vitamin K and potassium.

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The gas-phase reaction follows an elementary rate law and is to be carried out first in a PFR and then in a separate experiment

astraxan [27]

Answer:

The activation energy is $=8.1\,kcal\,mol^{-1}$

Explanation:

The gas phase reaction is as follows.

$A \rightarrow B+C$

The rate law of the reaction is as follows.

$-r_{A}=kC_{A}$

The reaction is carried out first in the plug flow reactor with feed as pure reactant.

From the given,

Volume "V" = $10dm^{3}$

Temperature "T" = 300 K

Volumetric flow rate of the reaction $v_{o}=5dm^{3}s$

Conversion of the reaction "X" = 0.8

The rate constant of the reaction can be calculate by the following formua.

$V= \frac{v_{0}}{k}[(1+\epsilon )ln(\frac{1}{1-X}-\epsilon X)]$

Rearrange the formula is as follows.

$k= \frac{v_{0}}{V}[(1+\epsilon )ln(\frac{1}{1-X}-\epsilon X)]............(1)$

The feed has Pure A, mole fraction of A in feed $y_{A_{o}}$ is 1.

$\epsilon =y_{A_{o}}\delta$

$\delta$ = change in total number of moles per mole of A reacte.

$=1(2-1)=1$

Substitute the all given values in equation (1)

$k=\frac{5m^{3}/s}{10dm^{3}}[(1+1)ln \frac{1}{1-0.8}-1 \times 0.8] = 1.2s^{-1}$

Therefore, the rate constant in case of the plug flow reacor at 300K is $1.2s^{-1}$

The rate constant in case of the CSTR can be calculated by using the formula.

$\frac{V}{v_{0}}= \frac{X(1+\epsilon X)}{k(1-X)}.............(2)$

The feed has 50% A and 50% inerts.

Hence, the mole fraction of A in feed $y_{A_{o}}$ is 0.5

$\epsilon =y_{A_{o}}\delta$

$\delta$ = change in total number of moles per mole of A reacted.

$=0.5(2-1)=0.5$

Substitute the all values in formula (2)

$\frac{10dm^{3}}{5dm^{3}}=\frac{0.8(1+0.5(0.8))}{k(1-0.8)}=2.8s^{-1}$

Therefore, the rate constant in case of CSTR comes out to be $2.8s^{-1}$

The activation energy of the reaction can be calculated by using formula

$k(T_{2})=k(T_{1})exp[\frac{E}{R}(\frac{1}{T_{1}}-\frac{1}{T_{2}})]$

In the above reaction rate constant at the two different temperatures.

Rearrange the above formula is as follows.

$E= R \times(\frac{T_{1}T_{2}}{T_{1}-T_{2}})ln\frac{k(T_{2})}{k(T_{1})}$

Substitute the all values.

$=1.987cal/molK(\frac{300K \times320K}{320K \times300K})ln \frac{2.8}{1.2}=8.081 \times10^{3}cal\,mol^{-1}$

$=8.1\,kcal\,mol^{-1}$

Therefore, the activation energy is $=8.1\,kcal\,mol^{-1}$

8 0

2 years ago

1.Which statement best describes an oxidation-reduction reaction?(1 point)

Nataly_w [17]

Answer:

Explanation:

7 0

3 years ago

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GenaCL600 [577]

Answer:

Huh?

Explanation:

4 0

2 years ago

A solution is prepared by dissolving 215 grams of methanol, ch3oh, in 1000. grams of water. what is the freezing point of this s

Leya [2.2K]

Answer : The freezing point of the solution is, 260.503 K

Solution : Given,

Mass of methanol (solute) = 215 g

Mass of water (solvent) = 1000 g = 1 kg (1 kg = 1000 g)

Freezing depression constant = $1.86^oC/m=1.86Kkg/mole$

Formula used :

$\Delta T_f=K_f\times m\\T^o_f-T_f=K_f\times \frac{w_{solute}}{M_{solute}\times w_{solvent}}$

where,

$T^o_f$ = freezing point of water = $100^oC=273K$

$T_f$ = freezing point of solution

$K_f$ = freezing point constant

$w_{solute}$ = mass of solute

$w_{solvent}$ = mass of solvent

$M_{solute}$ = molar mass of solute

Now put all the given values in the above formula, we get

$273K-T_f=(1.86Kkg/mole)\times \frac{215g}{(32g/mole)\times (1kg)}$

By rearranging the terms, we get the freezing point of solution.

$T_f=260.503K$

Therefore, the freezing point of the solution is, 260.503 K

6 0

2 years ago

What chemical reaction happens when mixing iron and copper

stiv31 [10]

i looked it up watched a video and i saw that rusting occured hope this helped let me know if it did and rate me from ok good great or godly.

7 0

2 years ago