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3 years ago

Which part anchors plants in the ground?

Chemistry

1 answer:

Murrr4er [49]3 years ago

3 0

The roots help anchor plants into the ground.

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My coin jar has 645 quarters in it. If one Wakandan Vibranium Dollar (WVD) is worth $2.72 U.S., how many WVD can I get for my qu

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3 years ago

Match the project to the appropriate field of chemistry (inorganic chemistry,

BlackZzzverrR [31]

Chemistry is composed of many sub-disciplines such as inorganic chemistry, physical chemistry, biochemistry, organic chemistry, analytical chemistry etc. The following is a matching of certain projects against the sub-discipline in chemistry where they rightfully belong.

1) Determine the composition of a moon rock sample..... analytical chemistry

2) Do research on making a new medicine to treat high blood pressure..... biochemistry

3) Investigate ways to regulate the rate of gasoline burning in an automobile engine......physical chemistry

4) Develop a plastic that can be decomposed by bacteria......organic chemistry

5) Improve the method for extracting iron from iron ore.....inorganic chemistry

The sub-disciplines of chemistry all work together to make the world a better place. The science of chemistry is very pivotal hence it is applicable in every area of science and technology.

Analytical chemistry, as the name implies, deals with "analyzing" or finding out the components of materials.

Biochemistry is concerned with the study of molecules that have biological activity such as medicine to treat high blood pressure.

One key area of physical chemistry is chemical kinetics which discusses rates of chemical reactions. This sub-discipline is important when investigate ways to regulate the rate of gasoline burning in an automobile engine.

Organic chemistry is the chemistry of carbon compounds. It studies compounds that contain long chains of carbon such as those found in plastics.

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Learn more: brainly.com/question/13428382

6 0

3 years ago

One number is three times of the other and their arithmetic mean is 10 find them

Marysya12 [62]

x = 10, y = 20/6

<h3>Further explanation</h3>

Given

one number is three times of the other

their arithmetic mean is 10

Required

The numbers

Solution

Suppose the numbers you are looking for are x and y, then :

x = 3y (equation 1)

The arithmetic mean : the average of values

(x+3y)/2=10

x+3y = 20 (equation 2)

Substitute equation 1 into equation 2

3y+3y=20

6y=20

y = 20/6

from equation 1 :

x= 3 x 20/6

x = 60/6

x = 10

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3 years ago

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3 years ago

Read 2 more answers

Determine the oxidation numbers of all the elements in the unbalanced reactions. Then, balance each redox reaction in a basic so

givi [52]

Answer for 1:

- Oxidation number of Mn in MnO4^-1= +7

- Oxidation number of O in MnO4^-1= -2

- Oxidation number of C in C2O4^-2= +3

- Oxidation number of O in C2O4^-2= -2

- Oxidation number of Mn in MnO2= +4

- Oxidation number of O in MnO2= -2

- Oxidation number of C in CO2= +4

- Balanced redox equation in basic solution:

$3C_2O_4^{-2}+2MnO_4^{-1}+4H_2O\operatorname{\rightarrow}6CO_2\text{ +}2MnO_2\text{ + }8OH^-$

Explanation for 1:

1st) To determine the oxidation numbers, it is necessary that the total sum of the charges is equal to that of the molecule or ion in the equation.

• Oxidation numbers in MnO4-,:

We know that the oxidation number for oxygen is -2, then we multiply it by the subscript 4 to find the whole charge of oxygen in this molecule.

Oxygen oxidation number: -2 x 4 = -8

Since the total charge of the molecule is -1, by difference, we will know that the oxidation number of Mn will be +7:

$\begin{gathered} Mn^{+7}O_4^{-2} \\ +7+[(-2*4)]=-1 \end{gathered}$

To confirm that the oxidation number that we determined exists for that element, we can check the Periodic Table of Elements.

We proceed in the same way with all molecules.

• Oxidation numbers in C2O4-2,:

$\begin{gathered} C_2^{+3}O_4^{-2} \\ (+3*2)+[(-2)*4]= \\ +6-8=-2 \end{gathered}$

• Oxidation numbers in MnO2,:

$\begin{gathered} Mn^{+4}O_2^{-2} \\ +4+[(-2)*2]= \\ +4-4=0 \end{gathered}$

• Oxidation numbers in CO2,:

$\begin{gathered} C^{+4}O_2^{-2}_ \\ +4+[(-2)*2]= \\ +4-4=0 \end{gathered}$

2nd) Now that we know the oxidation number os each atom in the reaction, then we can find the element that is oxidized and the element that is reduced.

We can see that Mn goes from +7 to +4, the Mn atom is reduced. And, the carbon atom goes from +3 to +4 so it oxidizes.

3rd) It is necessary to write the oxidation reaction and the reduction reaction separately and balancing all elements except oxygen and hydrogen:

Oxidation:

$C_2O_4^{-2}\text{ }\rightarrow\text{ 2}CO_2\text{ + 2}e^-_$

Reduction:

$MnO_4^{-1}\text{ + 3}e^-\rightarrow MnO_2$

4th) Since the reaction occurs in a basic solution, we must add water (H2O) to balance the oxygen atoms and hydroxyl ion (OH-) to balance the hydrogen atoms. In this case, the reduction reaction is the only one that needs to be balanced with water and hydroxyl ion.

$MnO_4^{-1}\text{ + 3}e^-\text{ +2}H_2O\operatorname{\rightarrow}MnO_2\text{ + 4}OH^-$

5th) It is necessary to balance the electrons in each half-reaction. So, we multiply each half-reaction by the number of electrons in the other half-reaction:

Oxidation:

$\begin{gathered} (C_2O_4^{-2}\operatorname{\rightarrow}\text{2}CO_2\text{ + 2}e_^-)*3 \\ 3C_2O_4^{-2}\operatorname{\rightarrow}6CO_2\text{ + 6}e^- \end{gathered}$

Reduction:

$\begin{gathered} (MnO_4^{-1}\text{ + 3}e^-\text{ + 2}H_2O\operatorname{\rightarrow}\text{ MnO}_2\text{ }+4OH^-)*2 \\ 2MnO_4^{-1}\text{ + 6}e^-\text{ + 4}H_2O\operatorname{\rightarrow}\text{ 2MnO}_2\text{ }+8OH^- \end{gathered}$

6th) We need to cancel out everything that is repeated on opposite sides of the reactions, including the electrons.

Finally, we can write the balanced redox equation:

$3C_2O_4^{-2}+2MnO_4^{-1}+4H_2O\operatorname{\rightarrow}6CO_2\text{ +}2MnO_2\text{ + }8OH^-$

6 0

1 year ago