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zhenek [66]
3 years ago
6

Given f(x), find g(x) and h(x) such that f(x) = g(h(x)) and neither g(x) nor h(x) is solely x.

Mathematics
1 answer:
aniked [119]3 years ago
6 0

Answer:

Please look at the different answers. I wasn't 100% sure what your expression was.

Step-by-step explanation:

If you mean 2/(5x-1) then g(x) will take the fraction into account with a constant 2 for the numerator and a variable for the denominator since that is where our variable is so g(x)=2/x.

Now h(x)=5x-1 since if you plug in 5x-1 into 2/x where x is you will get our original expression.

Now if you did mean (2/5)x-1 I would take notice of where the variable is which is in (2/5)x so g(x)=x-1 where h(x)=(2/5)x since if you plug (2/5)x in place of the x in x-1 you will get the original.

Please let me know if I didn't interpret your expression correctly.

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3 years ago
In the xy-plane, the equations x + 2y = 10 and
konstantin123 [22]

By solving given equations, the value of c is 30.

Given two equations

x + 2y = 10 and

3x + 6y = c

These lines represents the same line for some constant c.

Value of c:

x + 2y = 10-------------(1)

3x + 6y = c-------------(2)

Dividing equation (2) by 3

\frac{3x}{3}+ \frac{6y}{3} =\frac{c}{3}

After solving the above equation, we get

x + 2y = c/3-----------(3)

Remember that a line is written as ax + by = c, in our case, both lines have a =1 and b = 2. Therefore, in orther that the two lines are equal, we need that, 10 = c/3

c = 10 × 3 = 30

c = 30

Therefore,

The value of c is 30.

Find out more information about equations here

brainly.com/question/21952977

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