Answer:
904.78
Step-by-step explanation:
A sphere with a radius of 6 units has a volume of 904.78 units
Answer:
And rounded up we have that n=421
Step-by-step explanation:
We know that the sample proportion have the following distribution:

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by
and
. And the critical value would be given by:
The margin of error for the proportion interval is given by this formula:
(a)
And on this case we have that
and we are interested in order to find the value of n, if we solve n from equation (a) we got:
(b)
We assume that a prior estimation for p would be
since we don't have any other info provided. And replacing into equation (b) the values from part a we got:
And rounded up we have that n=421
Answer:
A. t(x) = 450 - 0.06x
Step-by-step explanation:
The layer which is originally 450 m thick is decreasing by 0.06 m.
450 - 0.06
... per day. x represents days.
0.06x
So,
450 - 0.06x
For the number before x you would look for the rise over the run. in this case you can see that there is an intersection at (-2,0) and (0,1) you find the difference ox each so you have 2/1 or just 2 you can tell that the line is going up so it is positive. for the addition part look at where the y intercept is in this case it is at positive one. this makes your equation y=2x+1
Answer:
With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is of at least 216.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error:

For this problem, we have that:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is
We need a sample size of at least n, in which n is found M = 0.04.







With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is of at least 216.