(4.50x10^16)/(6.02x10^24) = 7.5mols
7.5mols x 39.1= 293.25grams
Answer:
12 liters of oxygen are released from the decomposition of the peroxide.
Explanation:
The hydrogen peroxide is decomposed by this reaction:
2 H₂O₂ (l) → 2 H₂O (l) + O₂ (g)
Molar mass H₂O₂ = 34 g/m
Moles of peroxide: 36.5 g / 34 g/m = 1.07 moles
Ratio is 2:1, so 2 moles of peroxide will be decomposed in 1 mol of oxygen (exactly the half)
1.07 moles of peroxide will be decomposed in the half of moles, 0.54 moles
Let's apply the Ideal Gases law Equation to solve the volume
1 atm . V = 0.54 mol . 0.082 .273K
V = (0.54 mol . 0.082 .273K) / 1 atm → 12L
Answer:
Density = 8.75ml
Explanation:
Density = Mass / Volume
In this problem ...
Mass = 28 grams
Volume = 31.4ml - 28.2ml = 32ml (water displacement also)
∴Density = mass /volume = 28g/32ml = 8.75g/ml
Answer:
the answer is c kept in blue and with light
The equilibrium constant of a reaction is defined as:
"The ratio between equilibrium concentrations of products powered to their reaction quotient and equilibrium concentration of reactants powered to thier reaction quotient".
The reaction quotient, Q, has the same algebraic expressions but use the actual concentrations of reactants.
To solve this question we need this additional information:
<em>For this reaction, K = 6.0x10⁻² and the initial concentrations of the reactants are:</em>
<em>[N₂] = 4.0M; [NH₃] = 1.0x10⁻⁴M and [H₂] = 1.0x10⁻²M</em>
<em />
Thus, for the reaction:
N₂ + 3H₂ ⇄ 2NH₃
The equilibrium constant, K, of this reaction, is defined as:
And Q, is:
Where actual concentrations are:
[NH₃] = 1.0x10⁻⁴M
[N₂] = 4.0M
[H₂] = 2.5x10⁻¹M
Replacing:
<h3>Q = 1.6x10⁻⁷</h3>
As Q < K,
<h3>The chemical system will shift to the right in order to produce more NH₃</h3>
Learn more about chemical equililbrium in:
brainly.com/question/24301138