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daser333 [38]
3 years ago
14

Jose is loading his luggage into his car so that he can go to visit his grandmother. He lifts his suitcase up a 10 m staircase i

n his basement to the entrance of his garage with an average force of 60 N. How much work is performed by Jose in moving the suit case?
Physics
1 answer:
maxonik [38]3 years ago
3 0

Answer:

The work done on the suitcase is, W = 600 J

Explanation:

Given,

The average force exerted by Jose on his suitcase,  F = 60 N

Jose carried the suitcase to a distance, S = 10 m

The work done on the suitcase is given by the relation

                           <em>W = F x S</em>

Substituting the given values in the above equation,

                            W = 60 N x 10 m

                                 = 600 J

Hence, the work done on the suitcase is, W = 600 J

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1) A car accelerates uniformly from rest and reaches a speed of 19.8 m/s in 7 s. The diameter of a tire is 38.5 cm. Find the num
andre [41]

Answer:

1) 57 revolutions.

2) 4.52 m

3) 1531.2 m

Explanation:

Question 1:

Given:

Initial velocity, u = 0

Final velocity, v = 19.8\ m/s

Time, t = 7\ s

Acceleration, a = \frac{\textrm{Final velocity-Initial velocity}}{Time}=\frac{19.8}{7}=2.83\ m/s^2

Now, displacement of the tire is given as:

S=ut+\frac{a}{2}t^2\\S=0+\frac{2.83}{2}7^2=69.335\ m

Displacement of tire in 1 revolution is equal to its circumference.

Therefore, displacement in 1 revolution = \pi\times(Diameter)=\pi \times 38.5\times 10^{-2}=1.2095\ m

Now, number of revolutions is given as:

N=\frac{Total\ displacement}{Displacement\ per\ revolution}\\N=\frac{69.335}{1.2095}=57

Therefore, the number of revolutions are 57.

Question 2:

Given:

Radius of the wheel is, R=4.8\ m

Angle of rotation is, \theta=54°

Converting degree to radians, we get:

\theta=54\times \frac{\pi}{180}=0.3\pi

Now, path length is given as:

L=R\theta=(4.8)(0.3\pi)=1531.2\ m

Therefore, the path length of a point on the wheel is 4.52 m

Question 3:

Radius of the wheel is, R=4.8\ m

Angle of rotation is, \theta=319 radians

Now, path length is given as:

L=R\theta=(4.8)(319)=4.52\ m

Therefore, the path length of a point on the wheel is 1531.2 m.

7 0
3 years ago
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