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2 years ago

10. If a plane travels north for 2.5 hours at a velocity of 150 km/hr what distance did it travel?

Physics

1 answer:

salantis [7]2 years ago

4 0

Answer:

375 km

Explanation:

Using the equation, d = vt, we simply plug in the numbers:

v = 150 km/hr

t = 2.5 h

d = (150 km/hr)*(2.5 h)

d = 375 km

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First change km/ s into m/s, then use the formula
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3 years ago

At a location near the equator, the earth’s magnetic field is horizontal and points north. An electron is moving vertically upwa

ivann1987 [24]

Answer:

(b) EAST

Explanation:

you can assume that the magnetic field points rightward, that is, in the positive x direction (NORTH). Furthermore, you can assume that the direction of the motion of the electron is in the positive y direction. Hence, you have:

$\vec{B}=B_o\hat{i}\\\\\vec{v}=v_o\hat{j}$

You use the Lorentz formula to known which is the direction of the magnetic force over the electron:

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which implies the cross product between the unitary vecors j and i, that is

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3 years ago

Read 2 more answers

Question 13 (1 point)

KonstantinChe [14]

Answer:

Reflective clothing. So vehicles can see them and stuff.

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2 years ago

How much energy will a stock tank heater rated at 1790 Watts use in a 24 hour period? 1. 1790 × 24 × 3600 Joules 2. 1790 × 24 ×

Rashid [163]

<h2>Option 1 is the correct answer.</h2>

Explanation:

Power of heater, P = 1790 W

Time used, t = 24 hours = 24 x 60 x 60 = 24 x 3600 s

We have the equation

$\texttt{Power}=\frac{\texttt{Energy}}{\texttt{Time}}$

We need to find energy,

Substituting

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Energy = 1790 x 24 x 3600 J

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3 years ago

A 0.11 N m torque is applied to a fan that was initially at rest. The fan has moment of inertia of 0.034 kg m2. Determine the ki

Mars2501 [29]

Answer:

2.72*10-3 Joules

Explanation:

From Newton's second law of motion

F=ma

$\tau=I*\alpha$

given

$\tau= 0.11Nm\\\\I=0.034kgm^2\\\\t= 8s\\\\\alpha=?$

$\alpha =0.11/0.034\\\\\alpha=3.23 rad/s^2$

the angular velocity is

$\omega = \alpha/t\\\\\omega =3.23/8\\\\\omega =0.4 rad/s$

$KE= 1/2*I* \omega^2$

$KE=1/2*0.034*0.4^2\\\\KE=1/2*0.034*0.16\\\\KE=0.00272\\\\KE=2.72*10^-3J$

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3 years ago