Answer:
more than 51.45 N
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<u>We are given:</u>
Mass of the television = 15 kg
Coefficient of Static friction = 0.35
<u>Minimum force required to move the television:</u>
<u>Normal Force:</u>
We know that the normal force is equal and opposite to the Weight of the television
Weight of the television = Mg
[<em>where m is the mass and g is the acceleration due to gravity</em>]
Weight = 15 * 9.8
Weight = 147 N
<u>Force of Friction:</u>
We are given the coefficient of Friction = 0.35
We know that coefficient of Friction = Force of friction / Normal Force
<em>replacing the variables</em>
0.35 = Force of Friction / 147
Force of Friction = 147 * 0.35 [<em>multiplying both sides by 147</em>]
Force of Friction = 51.45 N
Since a force of 51.45 N is will be applied opposite to the direction of application of Force, the television will only move when we apply more force than 51.45 N
