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3 years ago

True or false a solid object can cast a shadow

Physics

2 answers:

nordsb [41]3 years ago

8 0

Yes, it is possible.

elena55 [62]3 years ago

7 0

That would be true because a solid object can cast a shadow

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An early method of measuring the speed of light makes use of a rotating slotted wheel. A beam of light passes through one of the

Readme [11.4K]

Answer:

4.7 x 10³ rad / s

Explanation:

During the time light goes and comes back , one slot is replaced by next slot while rotating before the light source

Time taken by light to travel a distance of 2 x 500 m is

= (2 x 500) / 3 x 10⁸

= 3.333 x 10⁻⁶ s .

In this time period, two consecutive slots come before the source of light one after another by rotation. There are 400 slots so time taken to make one rotation

= 3.333 x 10⁻⁶ x 400

= 13.33 x 10⁻⁴ s

This is the time period so

T = 13.33 X 10⁻⁴

Angular speed

= 2π / T

= $\frac{2\times3.14}{13.33\times10^{-4}}$

4.7 x 10³ rad / s

5 0

3 years ago

Two loudspeakers on a concert stage are vibrating in phase. A listener 50.5 m from the left speaker and 26.0 m from the right on

mixer [17]

To solve this problem, it is necessary to apply the concepts related to the constructive interference caused by the wavelengths of the sound traveling in the air.

From the definition of constructive interference we know that

$\Delta x = n \lambda \rightarrow \lambda = \frac{\Delta x}{n}$

Where

$\Delta x =$ Distance between speakers

n = Integer which represent he number of repetition of the spectrum

$\lambda =$ Wavelength

At the same time the frequency is subject to the form,

$f = \frac{v}{\lambda}$

Where

$v = 343m/s \rightarrow$ Velocity (of the sound at this case)

From our given values we have to $\Delta x$ is

$\Delta x = 50.5m-26m$

$\Delta x = 24.5m$

The wavelength would be subject to the sound spectrum therefore for n = 1,

$\lambda = \frac{\Delta x}{n}$

$\lambda = \frac{24.5}{1}$

$\lambda = 24.5m$

Then the frequency would be,

$f = \frac{v}{\lambda}$

$f = \frac{343}{24.5}$

$f = 14Hz$

For the value of n = 2,

$\lambda = \frac{\Delta x}{n}$

$\lambda = \frac{24.5}{2}$

$\lambda = 12.25m$

Then the frequency would be,

$f = \frac{v}{\lambda}$

$f = \frac{343}{12.25}$

$f = 28Hz$

For n = 3,

$\lambda = \frac{\Delta x}{n}$

$\lambda = \frac{24.5}{3}$

$\lambda = 8.167m$

Then the frequency would be,

$f = \frac{v}{\lambda}$

$f = \frac{343}{12.25}$

$f = 42Hz$

From the frequencies obtained we can identify that the two lowest frequencies that can be heard due to constructive interference are 28Hz and 42Hz

5 0

3 years ago

A uranium nucleus 238U may stay in one piece for billions of years, but sooner or later it decays into an α particle of mass 6.6

ale4655 [162]

Answer: The recoil speed is - 8.9604. $10^{4}$ m/s.

Explanation: According to the Third Law of Newton, every action has an oppsite and equal reaction, and the Second Law of Newton, Force=mass·acceleration. Acceleration is a variation in velocity by any given time, so Force = mass·velocity·time.

Combining the two laws, there is : m1·v1 = - m2·v2. This is the Law of Conservation of Momentum.

Substituting and calculating:

v2 = - ( $\frac{m1}{m2}$ ) · v1

v2 = - $\frac{6.64.10^{-27} }{3.88.10^{-25} }$ · 5.24. $10^{6}$

v2 = - 8.9604. $10^{4}$

The recoil speed of the thorium nucleus is - 8.9604. $10^{4}$ m/s.

8 0

4 years ago

Need help finding the average speed.

Snowcat [4.5K]

Explanation:

To find the average of these numbers, we just have to add the three numbers together and divide by 3.

2.07 + 0. 74 + 1.33 = 4.14. 4.14 / 3 = 1.38
1.09 + 1.40 + 0.31 = 2.8. 2.8 / 3 ≈ 9.3333333/ 9 1/3
0.95 + 1.61 + 0.56 = 3.12 / 3 = 1.04
0.81 + 1.89 + 1.08 = 3.78 / 3 = 1.26

5 0

4 years ago

Can a observation be accurate but not precise?

laila [671]

Sure
"Mount Everest is 29,000 feet tall" or in scientific terms 2.9E4
This statement/observation is accurate to 2 decimal places. It is precise only to (perhaps) the nearest thousand feet.
More precise
"Mount Everest is 29,029 feet tall"

3 0

4 years ago