From the information given, The mass of the bowling ball is 8 Kilograms and the momentum with which it is moving is 16 kg m/s.
We use the formula p = m × v
Where p is the momentum, m is the mass and v is the velocity.
We need velocity so we rewrite the equation thus:
P = mv, therefore p/m = v or v = p/m
In our case p = 16 and m = 8
v = p/m
v = 16/8
v = 2
Therefore the bowling ball is travelling at 2m/s
Report this clown who put the first answer he’s trying to get your ip
Answer: (a) t1 = omega1/alpha
(b) theta1 = 1/2 * alpha*theta1^2
(c) t2 = omega2/5*alpha
Explanation: see attachment
Answer:
Period of the signal.
Explanation:
So, this question is all about a concept in physics or astronomy which is called or known as Radiation Astronomy and Galactic Nuclei that are active. This concept talks most about Quasars; a powerful radiating object which derives its power from black holes.
When You take a look at Quasars, we get the to know that the more you think you can see, the more they move away from us.
Thus, when "You are observing the radiation from a distant active galaxy and you notice that the amplitude of the signal varies in strength regularly over a certain period. The maximum possible size for the source of this radiation can now be calculated from the "PERIOD OF THE SIGNAL.
NB: not the amplitude but the period.
Answer:
Velocity of airplane is 500 km/h
Velocity of wind is 40 km/h
Explanation:
= Velocity of airplane in still air
= Velocity of wind
Time taken by plane to travel 1150 km against the wind is 2.5 hours
Time taken by plane to travel 450 km against the wind is 50 minutes = 50/60 hours
Subtracting the two equations we get
Applying the value of velocity of wind to the first equation
∴ Velocity of airplane in still air is 500 km/h and Velocity of wind is 40 km/h
