AAAASAAAAAAAAAAAAAAhdhddhd
12/1331
that is the answer. too lazy to explain
<em>-3x-y=10</em>
<em>4x-4y=8</em>
<em>or</em>
<em>y = -3x - 10 </em>
<em>P(0,-10) and P(-2, -4) on this line: Plot and connect with the Line.</em>
<em></em>
<em> </em>
<em>y = x - 2</em>
<em>P(0, -2) and (2,0) on this line: Plot and connect with the Line.</em>
<em>P(-2,-4) is the ordered pair that is the solution for this system of EQs</em>
<em>On may CHECK by substituting x= -2 and y = -4 into the EQs of these Lines</em>
<em></em>
<em>Hope this helps!!!</em>
The equation of a circle with center (h,k) and radius r is
(x-h)²+(y-k)²=r²
so
given center is (3,-4)
(x-3)²+(y-(-4))²=r²
(x-3)²+(y+4)²=r²
find r² by subsitutiong the point taht it passes through which is (6,5)
so
(6-3)²+(5+4)²=r²
3²+9²=r²
9+81=r²
90=r²
so
(x-3)²+(y+4)²=90 is da equation
4th equation
