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Vladimir79 [104]
3 years ago
5

How to breakdown fraction

Mathematics
2 answers:
Tamiku [17]3 years ago
7 0
Divide it by 2, since you can make it into a half.
MAVERICK [17]3 years ago
4 0
Divide the faction by 2 until you can't anyone
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Which of the following are polynomial functions? Check all that apply.​
steposvetlana [31]

Answer:

C and E

Step-by-step explanation:

A polynomial is a function where the only operation is an exponent on the variable. It can have just one term or many terms. For example, x^2 is a polynomial but x^2 / x+3 is not since it also contains division. This is a rational. Using this definition then only C and E are polynomials.

Choice A has a rational term. This is not polynomial.

Choice B has an exponent of -2 which is actually division. This is rational and not polynomial.

Choice D has a radical term with the variable. This is not polynomial.

7 0
3 years ago
It took 7 hours to mow 4 lawns. How many lawns can I mow in 35 hours? Confused.. Please Check!!!
blondinia [14]
<u>7</u>  <u>35</u>   4x35/7= 20 lawns<u>
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3 years ago
Alyssa is driving to Chicago, and she is traveling at 60 miles per hour. If Chicago is 96 miles away, how long will it take her
Leviafan [203]

Answer: C

Step-by-step explanation: 1hour 36minutea

8 0
3 years ago
Read 2 more answers
Solve the following system
scZoUnD [109]

Answer:

{x = -4 , y = 2 ,  z = 1

Step-by-step explanation:

Solve the following system:

{-2 x + y + 2 z = 12 | (equation 1)

2 x - 4 y + z = -15 | (equation 2)

y + 4 z = 6 | (equation 3)

Add equation 1 to equation 2:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - 3 y + 3 z = -3 | (equation 2)

0 x+y + 4 z = 6 | (equation 3)

Divide equation 2 by 3:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+y + 4 z = 6 | (equation 3)

Add equation 2 to equation 3:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+0 y+5 z = 5 | (equation 3)

Divide equation 3 by 5:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 3 from equation 2:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y+0 z = -2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 2 from equation 1:

{-(2 x) + 0 y+2 z = 10 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract 2 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = 8 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = -4 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Collect results:

Answer:  {x = -4 , y = 2 ,  z = 1

4 0
2 years ago
What is the constant of variation for the inverse variation? xy = 8
Advocard [28]

Answer:

  8

Step-by-step explanation:

The constant of variation is the constant in the equation: 8.

___

The equation can be rewritten to be

  y = 8/x

Compared to the generic equation for inverse variation, ...

  y = k/x

we see that the constant of variation (k) is the constant in the given equation, 8.

6 0
3 years ago
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