All categories

3 years ago

What electromagnetic wave can cause skin cancer?

2 answers:

6 0

UV radiation is dangerous and can cause skin cancer because of it’s high frequency, which can penetrate the skin. Too much of it can be fatal. Therefore the answer is ultraviolet radiation.

Monica [59]3 years ago

4 0

Answer: Ultraviolet Radiation

Explanation: Ultraviolet Radiation is the kind of electromagnetic radiation having wavelength in the range of 10 nm to 400 nm. It is shorter than the visible light.

The prime and major source of these radiations is the Sun. These radiations have some advantages as well as these are used for the security purposes but these advantages are negated with the impact they have on living beings.

These radiations attacks directly the DNA of the cells of the skin and can cause fatal and an incurable disease like cancer.

You might be interested in

Copper produces a green flame test. When is the green light emitted?

belka [17]

Answer: When you burned the skewer tip coated with copper sulfate the green light is emitted

Explanation:

when the copper is burned it makes a green light

8 0

3 years ago

Name three of the most sensitive parts of your body (Appropriate parts. Ex: finger, wrist, shoulder, etc.)

yKpoI14uk [10]

Inner thigh, eyes, brain

3 0

3 years ago

Freon−12 (CF2Cl2), widely used as a refrigerant and aerosol propellant, is a dangerous air pollutant. In the troposphere, it tra

nevsk [136]

Answer:

141g of CCl₄

Explanation:

First, we have to write the balanced equation.

CCl₄(g) + 2 HF(g) ⇄ CF₂Cl₂(g) + 2 HCl(g)

We can calculate how many moles of CF₂Cl₂ using the ideal gas equation.

V = 14.9 dm³ = 14.9 L

T = 21°C + 273.15 = 294.15 K

P = 1.48 atm

R = 0.08206 atm.L/mol.K

$P.V=n.R.T\\n=\frac{P.V}{R.T} =\frac{1.48atm.14.9L}{0.08206\frac{atm.L}{mol.K}.294.15K }=0.914mol$

We can use proportions to find the mass of CCl₄ required to obtain 0.914 moles of CF₂Cl₂. According to the balanced equation, 1 mol of CF₂Cl₂ is produced when 1 mol of CCl₄ reacts. And the molar mass of CCl₄ is 154 g/mol.

$0.914molCF_{2}Cl_{2}.\frac{1molCCl_{4}}{1molCF_{2}Cl_{2}} .\frac{154gCCl_{4}}{1molCCl_{4}} =141gCCl_{4}$

7 0

3 years ago

When 8.21 l of c3h8 (g) burn in oxygen, how many liters of oxygen are consumed? all gas volumes are measured at the same tempera

just olya [345]

<span>8.21 L of C3H8(g) Lets take c as the molar volume at that temperature.
c L <><> 5c L
C3H8 (g) + 5O2 (g) --> 3CO2 + 4H2O + Q
8.21 L <><> x L
x = (8.21 * 5c)/c = 8.21 * 5 = 41.05 L O2 consumed for a 100% yield.</span>

5 0

3 years ago

2.<br> How many moles are contained in 0.800 g of calcium chloride (CaCl2)?

Ronch [10]

The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Calcium Chloride, or 110.984 grams.

7 0

3 years ago