(cube root of 5) * sqrt(5)
--------------------------------- = ?
(cube root of 5^5)
This becomes easier if we switch to fractional exponents:
5^(1/3) * 5^(1/2) 5^(1/3 + 1/2) 5^(5/6)
------------------------ = --------------------- = ------------- = 5^[5/6 - 5/3]
[ 5^5 ]^(1/3) 5^(5/3) 5^(5/3)
Note that 5/6 - 5/3 = 5/6 - 10/6 = -5/6.
1
Thus, 5^[5/6 - 5/3] = 5^(-5/6) = --------------
5^(5/6)
That's the correct answer. But if you want to remove the fractional exponent from the denominator, do this:
1 5^(1/6) 5^(1/6)
---------- * ------------- = -------------- (ANSWER)
5^(5/6) 5^(1/6) 5
It's 78π inches so probably d.
Answer:
(sss) condition
Step-by-step explanation:
hope the ans helped you
Answer:
Domain is all the possible x-values that can be plugged in and range is all the possible y-values that can be outputs. f(x)=1x can have any number as an input except for zero. If we plug in zero for x , then we would be dividing by zero which is impossible. Thus the domain is all real numbers except for zero.
Step-by-step explanation:
Answer:
<em>Isolate the variable by subtracting 7 from all 3 parts of the inequality, and then dividing each part by 2. To solve inequalities like a < x < b, use the addition and multiplication properties of inequality to solve the inequality for x.</em>
<em>Hope this was able to help you </em>