the overall equation for the conversation of pyruvate to acetyl COA is as below
CH3COO-COO- + NAD+ + HS-COA = ch3-COO-S -COA +NADH +CO2
The oxidation of pyruvate led to a conversation of NAD+ to NADH and produces acetyl COA and CO2
Answer:
The equation: (NH₄)₂SO₄ = 2NH4(+) + SO4(-2)
The number of moles = 5 g / 132.14 g/mol = 0.038 mol
The number of molecules = 0.038 X 6.022x10^23 = 2.29x10^23
the number of positive ions present in the ammonium sulphate solution:
2 positive ions for every 1 molecule of (NH₄)₂SO₄
so 2 x 2.29x10^23 = 4.58x10^23
the number of negative ions present in the ammonium sulphate solution
1 negative ion for every 1 molecule of (NH₄)₂SO₄
so 1 x 2.29x10^23 = 2.29x10^23
the total number of ions present in the ammonium sulphate solution
4.58x10^23 + 2.29x10^23 = 6.87x10^23
Bsjsgsusgsjdgsbsbsjshsgshshs
The six metalloids are boron, silicon, germanium, arsenic, antimony, and tellerium.
