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3 years ago

You chill your reaction in an ice bath when adding nitric acid to the sulfuric acid. why?

1 answer:

4 0

The reaction of nitric acid and sulfuric acid is highly exothermic so it releases a lot of heat. If the temperature is not controlled, the reaction could go into thermal runaway, which is potentially extremely hazardous.

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What experimental evidence was provided for the nuclear model of an atom

UkoKoshka [18]

Alpha particles bouncing off of gold foil.

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3 years ago

Which statement about electrons is not true?a. One electron state is a bonding orbital between nucleib. One electron state is an

NemiM [27]

Answer:

b. One electron state is an anti-bonding orbital, which results in an absence of electron density between atoms.

Explanation:

8 0

3 years ago

The metabolic oxidation of glucose, C6H12O6, in our bodies produces CO2, which is expelled from our lungs as a gas.

enot [183]

Answer:

$\large \boxed{\text{21.6 L}}$

Explanation:

We must do the conversions

mass of C₆H₁₂O₆ ⟶ moles of C₆H₁₂O₆ ⟶ moles of CO₂ ⟶ volume of CO₂

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ: 180.16

C₆H₁₂O₆ + 6O₂ ⟶ 6CO₂ + 6H₂O

m/g: 24.5

(a) Moles of C₆H₁₂O₆

$\text{Moles of C$_{6}$H$_{12}$O}_{6} = \text{24.5 g C$_{6}$H$_{12}$O}_{6}\times \dfrac{\text{1 mol C$_{6}$H$_{12}$O}_{6}}{\text{180.16 g C$_{6}$H$_{12}$O}_{6}}\\\\= \text{0.1360 mol C$_{6}$H$_{12}$O}_{6}$

(b) Moles of CO₂

$\text{Moles of CO}_{2} =\text{0.1360 mol C$_{6}$H$_{12}$O}_{6} \times \dfrac{\text{6 mol CO}_{2}}{\text{1 mol C$_{6}$H$_{12}$O}_{6}} = \text{0.8159 mol CO}_{2}$

(c) Volume of CO₂

We can use the Ideal Gas Law.

pV = nRT

Data:

p = 0.960 atm

n = 0.8159 mol

T = 37 °C

(i) Convert the temperature to kelvins

T = (37 + 273.15) K= 310.15 K

(ii) Calculate the volume

$\begin{array}{rcl}pV &=& nRT\\\text{0.960 atm} \times V & = & \text{0.8159 mol} \times \text{0.082 06 L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1} \times \text{310.15 K}\\0.960V & = & \text{20.77 L}\\V & = & \textbf{21.6 L} \\\end{array}\\\text{The volume of carbon dioxide is $\large \boxed{\textbf{21.6 L}}$}$

7 0

2 years ago

How many moles of oxygen are needed to react with 100.0 grams of aluminum?

Tasya [4]

Answer:

Explanation:

8 0

3 years ago

A solution is made by dissolving 10.20 grams of glucose (C6H12O6) in 355 grams of water. What is the freezing point depression o

Ludmilka [50]

Answer:

0.297 °C

Step-by-step explanation:

The formula for the freezing point depression ΔT_f is

ΔT_f = iK_f·b

i is the van’t Hoff factor: the number of moles of particles you get from a solute.

For glucose,

glucose(s) ⟶ glucose(aq)

1 mole glucose ⟶ 1 mol particles i = 1

Data:

Mass of glucose = 10.20 g

Mass of water = 355 g

ΔT_f = 1.86 °C·kg·mol⁻¹

Calculations:

(a) Moles of glucose

n = 10.20 g × (1 mol/180.16 g)

= 0.056 62 mol

(b) Kilograms of water

m = 355 g × (1 kg/1000 g)

= 0.355 kg

(c) Molal concentration

b = moles of solute/kilograms of solvent

= 0.056 62 mol/0.355 kg

= 0.1595 mol·kg⁻¹

(d) Freezing point depression

ΔT_f = 1 × 1.86 × 0.1595

= 0.297 °C

3 0

3 years ago