A cone of depression occurs in an aquifer when groundwater is pumped from a well. In an unconfined aquifer, this is an actual depression of the water levels. In confined aquifers, the cone of depression is a reduction in the pressure head surrounding the pumped well.
Answer:
A) solute - NaCl, solvent - water
B) solute - O2 and other gases, solvent - N2
C) solute - ethanol, solvent - water
D) solute - tin, solvent - copper
Explanation:
Solute(s) is/are the minor component(s) in a solution, dissolved in the solvent.
Solvent is the component of a solution that is present in the greatest amount. It is the substance in which the solute is dissolved.
If both solute and solvent exist in equal quantities (such as in a 50% ethanol, 50% water solution), the concepts of "solute" and "solvent" become less relevant, but the substance that is more often used as a solvent is normally designated as the solvent (in this example, water).
Answer:
Mass = 427.05 g
Explanation:
Given data:
Formula units of sodium chloride = 4.38 ×10²⁴
Mass of NaCl = ?
Solution:
One mole contain formula units = 6.022 ×10²³
4.38×10²⁴ formula units × 1mol /6.022 ×10²³ formula units
0.73 ×10¹ mol
7.3 mol
Mass of NaCl:
Mass = number of moles × molar mass
Mass = 7.3 mol × 58.5 g/mol
Mass = 427.05 g
Answer:
58.44 g of NaCl are needed.
Explanation:
Given data:
Mass of NaCl needed = ?
Volume of solution = 200 mL (200/1000 =0.2 L)
Molarity of solution = 5 M
Solution:
We will solve this problem through molarity formula.
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
Now we will put the values.
5 M = moles of solute / 0.2 L
Moles of solute = 5 mol/L × 0.2 L
Moles of solute = 1 mol
Mass of sodium chloride:
Mass = number of moles × molar mass
Mass = 1 mol × 58.44 g/mol
Mass = 58.44 g
Thus, 58.44 g of NaCl needed.
