Before mRNA leaves the nucleus of a eukaryotic cell, a cap is added to one end of the molecule, a poly A tail is added to the other end, introns are removed, and exons are spliced together. During translation the amino acids are assembled into a protein.
Answer:
69.55 (w/w) %
Explanation:
When NaHCO3 reacts with an acid HA, the reaction that occurs is:
NaHCO3 + HA → H2O + NaA + CO2
<em>Where 1 mole of NaHCO3 produce 1 mole of CO2</em>
<em />
Thus, we need to convert the mass of CO2 to moles using its molar mass (44g/mol). Then, based on the chemical equation, moles of CO2 produced are equal to moles of NaHCO3 in the mixture. With its molar mass -84g/mol- we can find the mass of NaHCO3 and mass percent:
<em>Moles CO2:</em>
0.561g * (1mol / 44g) = 0.01275 moles CO2 = Moles NaHCO3.
<em>Mass NaHCO3:</em>
0.01275 moles * (84g/mol) = 1.071g NaHCO3
<em>Mass percent:</em>
1.071g NaHCO3 / 1.54g sample * 100
<h3>69.55 (w/w) %</h3>
<span>We can solve this problem by assuming that the decay of
cyclopropane follows a 1st order rate of reaction. So that the
equation for decay follows the expression:</span>
A = Ao e^(- k t)
Where,
A = amount remaining at
time t = unknown (what to solve for) <span>
Ao = amount at time zero = 0.00560
M </span><span>
<span>k = rate constant
t = time = 1.50 hours or 5400 s </span></span>
The rate constant should
be given in the problem which I think you forgot to include. For the sake of
calculation, I will assume a rate constant which I found in other sources:
k = 5.29× 10^–4 s–1 (plug in the correct k value)
<span>Plugging in the values
in the 1st equation:</span>
A = 0.00560 M * e^(-5.29 × 10^–4 s–1 * 5400 s )
A = 3.218 <span>× 10^–4 M (simplify
as necessary)</span>
Weight is properly defined as how much gravity acts upon an object.
I hope this helps!
Answer:
atomic number 3
boiling point 1,342 °C (2,448 °F)
specific gravity 0.534 at 20 °C (68 °F)
oxidation state +1
electron configuration 2-1 or 1s22s1
Explanation:
i think this Is right 99% sure
