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Akimi4 [234]
3 years ago
8

2Mg + O2à MgO For this unbalanced chemical equation, what is the coefficient for oxygen when the equation is balanced? A. 1 B. 2

C. 3 D. 4
Chemistry
2 answers:
Vikki [24]3 years ago
7 0

Answer:

The answer to your question is the letter A. 1

Explanation:

Unbalanced chemical reaction

                      Mg  +  O₂  ⇒  MgO

               Reactants    Elements    Products

                       1            Magnesium       1

                       2           Oxygen              1

Balanced chemical reaction

                      2Mg  +  O₂  ⇒  2MgO

              Reactants    Elements    Products

                       2           Magnesium       2

                       2           Oxygen             2

Conclusion

The coefficients of the balanced equation are 2, 1, 2

beks73 [17]3 years ago
7 0

Answer:

The coefficient for oxygen, in this equation is 1

Explanation:

Step 1: The unbalanced equation

2Mg + O2 → MgO

Step 2: Balancing the equation

2Mg + O2 → MgO

On the left side we have 2x Mg, on the right side we have 1x Mg(in MgO).

To balance the amount of Mg we have to multiply MgO by 2.

Now the amount of O is on both sides also equal.

The equation is balanced.

2Mg + O2 → 2MgO

The coefficient for oxygen, in this equation is 1

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Ionic equation:

\text{H}_2\text{PO}_4^{-} + \text{HAsO}_4^{2-} \to \text{HPO}_4^{2-} + \text{H}_2\text{AsO}_4^{-}

The acid and base in a conjugate pair differ by only one proton \text{H}^{+}. The acid loses one proton to produce a conjugate base, whereas the base gains a proton to produce its conjugate acid.

\text{H}_2\text{PO}_4^{-} loses one proton to produce \text{HPO}_4^{2-} in this reaction.

\text{H}_2\text{PO}_4^{-} \to \text{H}^{+} + \text{HPO}_4^{2-}

Meanwhile, \text{HAsO}_4^{2-} gains one proton to form \text{H}_2\text{AsO}_4^{-}.

\text{HAsO}_4^{2-} + \text{H}^{+} \to \text{H}_2\text{AsO}_4^{-}

Therefore

  • \text{H}_2\text{PO}_4^{-} is the conjugate acid  \text{HPO}_4^{2-}, its conjugate base.
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Answer:

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The percentage of F in the compound =

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