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Akimi4 [234]
3 years ago
8

2Mg + O2à MgO For this unbalanced chemical equation, what is the coefficient for oxygen when the equation is balanced? A. 1 B. 2

C. 3 D. 4
Chemistry
2 answers:
Vikki [24]3 years ago
7 0

Answer:

The answer to your question is the letter A. 1

Explanation:

Unbalanced chemical reaction

                      Mg  +  O₂  ⇒  MgO

               Reactants    Elements    Products

                       1            Magnesium       1

                       2           Oxygen              1

Balanced chemical reaction

                      2Mg  +  O₂  ⇒  2MgO

              Reactants    Elements    Products

                       2           Magnesium       2

                       2           Oxygen             2

Conclusion

The coefficients of the balanced equation are 2, 1, 2

beks73 [17]3 years ago
7 0

Answer:

The coefficient for oxygen, in this equation is 1

Explanation:

Step 1: The unbalanced equation

2Mg + O2 → MgO

Step 2: Balancing the equation

2Mg + O2 → MgO

On the left side we have 2x Mg, on the right side we have 1x Mg(in MgO).

To balance the amount of Mg we have to multiply MgO by 2.

Now the amount of O is on both sides also equal.

The equation is balanced.

2Mg + O2 → 2MgO

The coefficient for oxygen, in this equation is 1

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Nataly_w [17]
Cl2(g) -------> Cl-(aq) + ClO-(aq) 

2e- + Cl2(g) -------> 2Cl-(aq) [reduction] 

4OH-(aq) + Cl2(g) -----------> 2ClO-(aq) + 2H2O(l) + 2e- [oxidation] 
______________________________________... 
2OH-(aq) + Cl2(g) --------> Cl-(aq) + ClO-(aq) + H2O(l)
4 0
3 years ago
What structures are found in plant cells that are not what structures are found in plant cells that are not me found in animal c
Amanda [17]

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3 0
3 years ago
What total volume of ozone measured at a pressure of 24.5 mmHg and a temperature of 232 K can be destroyed when all of the chlor
ddd [48]

Answer:

1.75272\ \text{m}^3

Explanation:

The breakdown reaction of ozone is as follows

CF_3Cl + UV \rightarrow CF_3 + Cl

Cl + O_3 \rightarrow ClO + O_2

O_3 + UV \rightarrow O_2 + O

ClO + O \rightarrow Cl + O_2

It can be seen that 2 moles of ozone is required in the complete cycle

So for 10 cycles, 20 moles of ozone is required

m = Mass of CF_3Cl = 15.5 g

M = Molar mass of CF_3Cl = 104.46 g/mol

P = Pressure = 24.5 mmHg

T = Temperature = 232 K

R = Gas constant = 62.363\ \text{L mmHg/K mol}

Number of moles is given by

n=\dfrac{m}{M}\\\Rightarrow n=\dfrac{15.5}{104.46}\\\Rightarrow n=0.1484\ \text{moles}

20\ \text{moles} = 20\times 0.1484 = 2.968\ \text{moles}

From ideal gas law we have

PV=nRT\\\Rightarrow V=\dfrac{nRT}{P}\\\Rightarrow V=\dfrac{2.968\times 62.363\times 232}{24.5}\\\Rightarrow V=1752.72\ \text{L}=1.75272\ \text{m}^3

For 20 cycles of the reaction the volume of the ozone is 1.75272\ \text{m}^3.

7 0
3 years ago
1) Define water gas<br>2) The skuLL is divided into two parts name them​
Triss [41]

• a fuel gas consisting mainly of carbon monoxide and hydrogen, made by passing steam over incandescent coke

• the cranium and the mandible.

hope it helps...!!!

5 0
2 years ago
The standard heats of formation for CO2(g), C2H6(g), and H2O(l) are -394.0 kJ/mol, -84.00 kJ/mol, and -286.0 kJ, respectively. W
Ivanshal [37]

Answer:

ΔH°r = -1562 kJ

Explanation:

Let's consider the following combustion.

C₂H₆(g) + 7/2 O₂(g) ⇒ 2 CO₂(g) + 3 H₂O(l)

We can calculate the standard heat of reaction (ΔH°r) using the following expression:

ΔH°r = ∑np × ΔH°f(p) - ∑nr × ΔH°f(r)

where,

ni are the moles of reactants and products

ΔH°f(i) are the standard heats of formation of reactants and products

The standard heat of formation of simple substances in their most stable state is zero. That means that ΔH°f(O₂(g)) = 0

ΔH°r = ∑np × ΔH°f(p) - ∑nr × ΔH°f(r)

ΔH°r = [2 mol × ΔH°f(CO₂) + 3 mol × ΔH°f(H₂O)] - [1 mol × ΔH°f(C₂H₆) + 7/2 mol × ΔH°f(O₂)]

ΔH°r = [2 mol × (-394.0 kJ/mol) + 3 mol × (-286.0 kJ/mol)] - [1 mol × (-84.00 kJ/mol) + 7/2 mol × 0]

ΔH°r = -1562 kJ

6 0
3 years ago
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