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3 years ago

PLZ HELP CHEM!!!!!!!!!!!!!!

Chemistry

2 answers:

pav-90 [236]3 years ago

5 0

the third answer 42.6L

PilotLPTM [1.2K]3 years ago

3 0

Answer:

The volume of the 84 grams of bromine gas at STP is 11.77 L.

Explanation:

Mass of bromine gas = 84 g

Moles of bromine gas = $\frac{84 g}{160 g/mol}=0.525 mol$

where,

P = Pressure of gas = 1 atm (at STP)

V = Volume of gas = ?

n = number of moles of gas = 0.0525 mol

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas = 273.15 K (at STP)

Putting values in above equation, we get:

$V=\frac{nRT}{P}$

$V=\frac{0.525 mol\times 0.0821 atm L/mol K\times 273.15 K}{1 atm}$

V = 11.77 L

The volume of the 84 grams of bromine gas at STP is 11.77 L.

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The solubility of oxygen in lakes high in the Rocky Mountains is affected by the altitude. If the solubility of O2 from the air

IceJOKER [234]

Answer:

$1.75\cdot 10^{-4} M$

Explanation:

Henry's law states that the solubility of a gas is directly proportional to its partial pressure. The equation may be written as:

$S = k_H p^o$

Where $k_H$ is Henry's law constant.

Our strategy will be to identify the Henry's law constant for oxygen given the initial conditions and then use it to find the solubility at different conditions.

Given initially:

$S_1 = 2.67\cdot 10^{-4} M$

Also, at sea level, we have an atmospheric pressure of:

$p = 1.00 atm$

Given mole fraction:

$\chi_{O_2} = 0.209$

According to Dalton's law of partial pressures, the partial pressure of oxygen is equal to the product of its mole fraction and the total pressure:

$p^o = \chi_{O_2} p$

Then the equation becomes:

$S_1 = k_H \chi_{O_2} p$

Solve for $k_H$ :

$k_H = \frac{S_1}{\chi_{O_2} p} = \frac{2.67\cdot 10^{-4} M}{0.209\cdot 1.00 atm} = 0.001278 M/atm$

Now we're given that at an altitude of 12,000 ft, the atmospheric pressure is now:

$p = 0.657 atm$

Apply Henry's law using the constant we found:

$S_2 = k_H \chi_{O_2} p = 0.001278 M/atm\cdot 0.209\cdot 0.657 atm = 1.75\cdot 10^{-4} M$

8 0

3 years ago

A baseball player hits a ball. Which is the best description of the energy of the ball as it flies over the pitcher’s head?

Elan Coil [88]

The right option is; b. mechanical

Mechanical energy is the best description of the energy of the ball as it flies over the pitcher’s head.

Mechanical energy is the energy that an object acquires due to its position or due to its motion. From the question, the baseball player has chemical potential energy (stored as food) which is transformed into work. As the baseball player hits the ball, there is energy exchange in which the ball acquires energy to perform its work. The energy obtained by the ball upon which work is done is called mechanical energy.

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3 years ago

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Name two elements, compounds and mixtures that are essential for living organisms. Also write why are they essential?

svlad2 [7]

elements:

calcium : for strong bones

Iron : maintaining haemoglobin for metabolism

compunds

sodium chloride : to maintain blood pressure and other life processes

Adenosine Triphosphate: for metabolism, to maintain rate of inhalation and exhalation of oxygen and to supply energy

Mixture:

I) gasoline : used as fuel

ii) cement : used in construction

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3 years ago

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The change in enthalpy that occurs in the process of converting reactants to products in a chemical reaction is called the _____

zheka24 [161]

Answer:

∆H or Enthalpy of the reaction

Explanation:

If ∆H is +ve

Reaction is exothermic
Example:-Combustion, mixing sodium/potassium in water

If ∆H is -ve

Reaction is endothermic
Ex:-Melting of ice

6 0

2 years ago

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What mass of sucrose (C12H22O11) should be combined with 546 g of water to make a solution with an osmotic pressure of 8.80 atm

lesya [120]

<u>Answer:</u> The mass of sucrose required is 69.08 g

<u>Explanation:</u>

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=iMRT$

Or,

$\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT$

where,

$\pi$ = osmotic pressure of the solution = 8.80 atm

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of solute (sucrose) = ?

Molar mass of sucrose = 342.3 g/mol

Volume of solution = 564 mL (Density of water = 1 g/mL)

R = Gas constant = $0.0821\text{ L.atm }mol^{-1}K^{-1}$

T = Temperature of the solution = 290 K

Putting values in above equation, we get:

$8.80atm=1\times \frac{\text{Mass of sucrose}\times 1000}{342.3\times 546}\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 290K\\\\\text{Mass of sucrose}=\frac{8.80\times 342.3\times 546}{1\times 1000\times 0.0821\times 290}=69.08g$

Hence, the mass of sucrose required is 69.08 g

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2 years ago