Question

PLZ HELP CHEM!!!!!!!!!!!!!!

Answer 1

the third answer 42.6L

Answer 2

Answer:

The volume of the 84 grams of bromine gas at STP is 11.77 L.

Explanation:

Mass of bromine gas = 84 g

Moles of bromine gas = $\frac{84 g}{160 g/mol}=0.525 mol$

where,

P = Pressure of gas = 1 atm (at STP)

V = Volume of gas = ?

n = number of moles of gas = 0.0525 mol

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas = 273.15 K  (at STP)

Putting values in above equation, we get:

$V=\frac{nRT}{P}$

$V=\frac{0.525 mol\times 0.0821 atm L/mol K\times 273.15 K}{1 atm}$

V = 11.77 L

The volume of the 84 grams of bromine gas at STP is 11.77 L.