Answer:
tan x = -3 (Answer A)
Step-by-step explanation:
We want to find the tangent of this angle "theta," and recall the trig identity
(sin x)^2 + (cos x)^2 = 1.
3√10
If sin x = -----------
10
90
then (sin x)^2 = ----------- = 9/10
100
and (cos x)^2 = 1 - 9/10 = 1/10
sin x 3√10/10
Then tan x = ---------- = -------------- = -3 (Answer A)
cos x 1√10/10
The tangent function is negative in Quadrant II. In Quadrant I tan x = +3
Answer:
h = 8.78
Step-by-step explanation:
Remark
Since this is a right angle triangle, you could find the area 2 different ways.
Area 1. Use the arms of the right angle to find the area.
Area = 1/2 * a * b
a = 9
b = 40
Area = 1/2 40 * 9
Area = 180 m^2
The other way is to multiply the height by the hypotenuse
h = ?
hypotenuse = 41
Area = 1/2 * 41 * h
But we already know the area
1/2 41 * h = 180 Multiply by 2
41 * h = 2 * 180
41 * h = 360 Divide by 41
h = 360 / 41
h = 8.78
The graph has a y-intercept of 2 and is shifted to the right 6 from the parent function.
The parent function, y=√x, looks like a parabola laid on its side. We generally only consider the positive square root unless told otherwise. Since we have √(x-6) instead of just √x, the graph is shifted to the right 6 units. The +2 at the end of the equation shifts the graph up 2.
-3(4x-1) = C. -12x + 3
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