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3 years ago

I really need help with these please

Mathematics

2 answers:

vladimir2022 [97]3 years ago

5 0

5. start at 0,0 left 1 up one
6. start at 0,0 down 3
7. start at 0,0 right 3 up 2
8. left 3 down 1
9. right 1, down 2
10.right 1, up 3

Free_Kalibri [48]3 years ago

5 0

For a - start on the middle line (at 0) going across (x-axis) and go left one, then go up one.
for b - start on the x-axis (at 0) and stay there (don't go up or down because its a 0) then go down 3 on the y-axis until you reach -3
for c - start on the x-axis (at 0) and go over to the right 3 spaces then go up 2 spaces
for d - start on the x-axis (at 0) and go left 3 times until you reach -3, then go down one space to -1
for e - start one x-axis (at 0) then go over 1 space then go down 2 spaces until you reach -2
for f - start on the x-axis (at 0) then go over 1 then go up 3 spaces
*** also your #4 is wrong, the point supposed to be (2,-2) and #3 is supposed to be (1,3)

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Solve | x + 6| - 7 = 8

Alex

Answer:

x = 9,-21

Step-by-step explanation:

Given:

$\displaystyle \large{|x+6|-7=8}$

Transport -7 to add 8:

$\displaystyle \large{|x+6|=8+7}\\\displaystyle \large{|x+6|=15}$

Cancel absolute sign and add plus-minus to 15:

$\displaystyle \large{x+6=\pm 15}$

Transport 6 to subtract ±15:

$\displaystyle \large{x=\pm 15-6}$

Consider:

$\displaystyle \large{x= 15-6}$ or $\displaystyle \large{x = -15-6}$

$\displaystyle \large{x=9}$ or $\displaystyle \large{x=-21}$

Solution:

$\displaystyle \large{x = 9}$ or $\displaystyle \large{x=-21}$

__________________________________________________________

Second Method

Given:

$\displaystyle \large{|x+6|-7=8}$

Transport -7 to add 8:

$\displaystyle \large{|x+6|=8+7}\\\displaystyle \large{|x+6|=15}$

Absolute Function Property:

$\displaystyle \large{|x-a| = \begin{cases} x-a \ \ (x \geq a) \\ -x+a \ \ (x < a) \end{cases}}$

Consider both intervals:

When x ≥ a then:

$\displaystyle \large{|x+6|=15}\\\displaystyle \large{x+6=15}$

Transport 6 to subtract 15:

$\displaystyle \large{x=15-6}\\\displaystyle \large{x=9}$

When x < a then:

$\displaystyle \large{|x+6|=15}\\\displaystyle \large{-(x+6)=15}\\\displaystyle \large{-x-6=15}$

Transport -6 to add 15:

$\displaystyle \large{-x=15+6}\\\displaystyle \large{-x=21}$

Transport negative sign to 21:

$\displaystyle \large{x=-21}$

Solution:

$\displaystyle \large{x=9}$ or $\displaystyle \large{x=-21}$

__________________________________________________________

Let me know if you have any questions regarding this question, my answer or explanation. Hope this answer and explanation helps you and good luck with your assignment!

3 0

2 years ago

. Simplify each of the following ratios in its simplest form. .36 : 132

viva [34]

Step-by-step explanation:

36 : 132

= 18 : 66

= 6 : 22

= 3 : 11

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3 years ago

Prove that the line passing through points A (4.1) and B (-1.3) is perpendicular to the line passing through points G (4, -2) an

Mumz [18]

Answer:

See below

Step-by-step explanation:

Find the slope of each line:

m(AB) = (3 - 1)/(- 1 - 4) = 2 / - 5 = - 2/5
m(GD) = (3 + 2)/(6 - 4) = 5/2

The product of the slopes is - 1, hence the lines are perpendicular:

- 2/5 * 5/2 = - 1

Equation of each line

Line AB

y - 1 = -2/5(x - 4) ⇒ y = - 2/5x + 8/5 + 1 ⇒ y = - 2/5x + 13/5

line GD

y + 2 = 5/2(x - 4) ⇒ y = 5/2x - 10 - 2 ⇒ y = 5/2x - 12

Their graph and intersection point is given in the attached picture

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2 years ago

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gregori [183]

D 25000 milligrams < 90 grams
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2 years ago

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SashulF [63]

Answer:

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Step-by-step explanation:

I'm not sure if I did the math right but this is what I got, I think it's right.

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