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ArbitrLikvidat [17]
2 years ago
6

An asset (not an automobile) placed in service in June 2018 has a depreciable basis of $35,000 and a recovery period of 5 years.

Assuming bonus depreciation is used, a half-year convention, and no expensing election, what is the maximum amount of cost that can be deducted in 2018?
Business
2 answers:
victus00 [196]2 years ago
8 0

Answer:

$35,000

Explanation:

The Tax Cuts and Jobs Act increased the percentage of bonus depreciation for qualifying assets from 50% to 100% for those assets acquired and put into service between September 27, 2017 and January 1, 2023. If this asset qualifies for a bonus depreciation, then you can depreciate 100% during the first year. You can also use the bonus depreciation with a section 179 expensing in order to depreciate expensive assets, but the section 179 expensing comes first and then the bonus depreciation.

Maurinko [17]2 years ago
5 0

Answer:

The Cost that can be deducted will be $3,500

Explanation:

     Bonus Depreciation=$35,000*50%=$17,500

     Now cost deductible in 2018 will be=$17,500/5=$3,500

Currently 50% bonus depreciation being deducted on assets as per new rulings.

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When including initial costs in a project's cash-flow, the relevant costs are those that henceforth will be spent on the project. Sunk costs are not to be included because they have already been incurred and cannot be recovered.

Research and Development costs have already been incurred and so are sunk costs. Hence they are not to be included in the initial cash-flow for the project.

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Leupold & Stevens, Inc., makes Leupold scopes for rifles and has introduced a new scope that has the quality and performance
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Penetration pricing

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Is a marketing strategy used by businesses to attract customers to a new service or product.  By offering lower price during its initial offering, thats the way they do.   The lower price, helps a new producto or service penetrate the market and attract customers .

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3 years ago
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It is B. passive income
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2 years ago
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In​ class, we discussed the differences between a contribution income statement versus the traditional approach​ (absorption whi
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3 years ago
If the world's population increased exponentially from 5.937 billion in 1998 to 6.771 billion in 2008 and continued to increase
Vaselesa [24]

Answer:

The world's population would have been 7.1137 billion in 2012, and this is 0.0437 billion (i.e. 7.1137 - 7.07 = 0.0437) higher compared to the population reference bureau estimate of 7.07 billion in July 2012.

Explanation:

This can be computed using the following exponential formula:

P(t) = P(0)a^t ............................ (1)

Where;

P(t) = World population in year t.

P(0) = World population in year 0 which is 1998 = 5.937 billion

a = base = ?

t = number of years

Substituting the value into equation (1), we have:

P(t) = 5.937 * a^t .......................................... (2)

Since we have 10 years from 1998 to 2008 (i.e. 2008 - 1998 = 10), we have:

P(t) = P(10) = World population in 2008 = 6.771 billion

t = 10

Substituting the value into equation (2) and solve for a, we have:

6.771 = 5.937 * a^10

a^10 = 6.771 / 5.937

a^10 = 1.1405

a = \sqrt[10]{1.405}

a = 1.013

Since we have 14 years from 1998 to 2012 (i.e. 2012 - 1998 = 14), we now have:

P(t) = P(14) = World population in 2012 = ?

P(0) = World population in year 0 which is 1998 = 5.937 billion

a = 1.013 as already calculated above

t = 14

Substituting the value into equation (1), we have:

P(14) = 5.937 * 1.013^14

P(14) = 5.937 * 1.192

P(14) = 7.1137 billion

Therefore, the world's population would have been 7.1137 billion in 2012, and this is 0.0437 billion (i.e. 7.1137 - 7.07 = 0.0437) higher compared to the population reference bureau estimate of 7.07 billion in july 2012.

6 0
3 years ago
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