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posledela
3 years ago
9

Which compound is an isomer of propanoic acid (CH3CH2COOH)?

Chemistry
2 answers:
arlik [135]3 years ago
5 0

Answer:

D) HCOOCH2CH3

Explanation:

An isomer of a compound is defined as a chemical substances with the same formula (That is, same atoms) but in different structures.

For propanoic acid, there are <em>3 atoms of C, 6 atoms of H and 2 atoms of oxygen.</em>

A) CH2CHCOOH . Here you have 3 atoms of C but 4 atoms of H. That means this compound is not an isomer.

B) CH3CH2CH2COOH . Here, there are 4 atoms of C. Thus, is not an isomer.

C) CH3CH(OH)CH2OH. This structure has 3 atoms of C, but 8 atoms of H. Thus, is not an isomer.

D) HCOOCH2CH3. Here, there are 3 atoms of C, 6 atoms of H and 2 atoms of O. Thus, this structure <em>is an isomer of propanoic acid.</em>

diamong [38]3 years ago
5 0

Answer:

D) HCOOCH2CH3

Explanation:

Option D is an isomer of propanoic acid because this compound has the same number of atoms as the acid; 3 carbons, 6 hydrogens and 2 oxygen. They may differ in some properties but their main difference must be their molecular structure, that is, the arrangement of their atoms.

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Draw a mechanism for this reaction. 5-hydroxypentanoic acid forms 2-oxanone in the presence of acid. draw all missing reactants
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Answer: -

The first step involves protonation of the carbonyl oxygen.

After protonation, the Alcohol oxygen now attacks the carbon of the carbonyl.

Thus a six membered ring is formed with 5 carbon atoms and 1 oxygen atom. The 1st position carbon atom has 2 OH groups.

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Thus 5-hydroxypentanoic acid forms a lactone or 2-oxanone in presence of acid.

3 0
3 years ago
A student was asked to prepare 500.0 mL of 6.0 M NaOH. The student measured 120.0 g of NaOH and placed it in a 1000 mL beaker. T
Morgarella [4.7K]

Answer:

The concentration of the solution will be much lower than 6M

Explanation:

To prepare a solution of a solid, the appropriate mass is taken and accurately weighed in a weighing balance and then made up to mark with distilled water.

From

n= CV

n = number of moles m/M( m= mass of solid, M= molar mass of compound)

C= concentration of substance

V= volume of solution

m=120g

M= 40gmol-1

V=500ml

120/40= C×500/1000

C= 120/40× 1000/500

C=6M

This solution will not be exactly 6M if the student follows the procedure outlined in the question. The actual concentration will be much less than 6M.

This is because, solutions are prepared in a standard volumetric flask. Using a 1000ml beaker, the student must have added more water than the required 500ml thereby making the actual concentration of the solution less than the expected 6M.

7 0
3 years ago
Calculate the time it takes for an object moving with a speed of 13m/s to travel 50 m
kykrilka [37]

Answer:

<h3>The answer is 3.85 s</h3>

Explanation:

The time taken can be found by using the formula

t =  \frac{d}{v}  \\

d is the distance covered

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From the question we have

t =  \frac{50}{13}  \\  = 3.846153...

We have the final answer as

<h3>3.85 s</h3>

Hope this helps you

7 0
3 years ago
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