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posledela
2 years ago
9

Which compound is an isomer of propanoic acid (CH3CH2COOH)?

Chemistry
2 answers:
arlik [135]2 years ago
5 0

Answer:

D) HCOOCH2CH3

Explanation:

An isomer of a compound is defined as a chemical substances with the same formula (That is, same atoms) but in different structures.

For propanoic acid, there are <em>3 atoms of C, 6 atoms of H and 2 atoms of oxygen.</em>

A) CH2CHCOOH . Here you have 3 atoms of C but 4 atoms of H. That means this compound is not an isomer.

B) CH3CH2CH2COOH . Here, there are 4 atoms of C. Thus, is not an isomer.

C) CH3CH(OH)CH2OH. This structure has 3 atoms of C, but 8 atoms of H. Thus, is not an isomer.

D) HCOOCH2CH3. Here, there are 3 atoms of C, 6 atoms of H and 2 atoms of O. Thus, this structure <em>is an isomer of propanoic acid.</em>

diamong [38]2 years ago
5 0

Answer:

D) HCOOCH2CH3

Explanation:

Option D is an isomer of propanoic acid because this compound has the same number of atoms as the acid; 3 carbons, 6 hydrogens and 2 oxygen. They may differ in some properties but their main difference must be their molecular structure, that is, the arrangement of their atoms.

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Answer:

C. 30 kJ

Explanation:

Hello there!

In this case, in agreement to the thermodynamic definition of the Gibbs free energy, in terms of enthalpy of entropy:

\Delta G= \Delta H-T\Delta S

It is possible to calculate the required G by plugging in the given entropy and enthalpy as shown below:

\Delta G=-220kJ/mol-5000K*-0.05kJ/mol*K\\\\\Delta G=30kJ/mol

Therefore, the answer is C. 30 kJ .

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2 years ago
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IgorLugansk [536]

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1 mole is equal to 6.022x10²³ particles as given, so:

1.5x10^{24} particles FeO_{2} (\frac{1mol}{6.022x10^{23}particles } )=2.49 molFeO_{2}

<h3>Answer:</h3>

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3 0
3 years ago
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<span>Fe(NO3)2
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6 0
3 years ago
When the volume of a gas is
Cerrena [4.2K]

Answer:

THE NEW VOLUME OF THE GAS IS 406 mL WHEN THE TEMPERATURE CHANGES FROM 765 K TO 315 K.

Explanation:

When the temperature changes from  765 K to 315K, the volume has changed from 986 mL to?

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T1 = 765 K

T2 = 315 K

V2 = unknown

Using Charles' equation of gas laws;

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V2 = V1 T2 / T1

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V2 = 0.406 L

V2 = 406 mL

So therefore, the volume of a gas changes from 986 mL to 406 mL as a result of a change in temperature from 765 K to 315 K.

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3 years ago
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