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kifflom [539]
2 years ago
15

1.(03.02 LC) Which of the following best defines weather? (3 points)

Chemistry
1 answer:
Monica [59]2 years ago
8 0

The atmospheric conditions at a particular time.

i did the test.

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A balloon that had a volume of 3.50 L at 25.0°C is placed in a hot room at 40.0°C. If the pressure remains constant at 1.00 atm,
choli [55]

Answer:

3.676 L.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R  is the general gas constant,

T is the temperature of the gas in K.

If n and P are constant, and have different values of V and T:

(V₁T₂) = (V₂T₁)

Knowing that:

V₁ = 3.5 L, T₁ = 25°C + 273 = 298 K,

V₂ = ??? L, T₂ = 40°C + 273 = 313 K,

Applying in the above equation

(V₁T₂) = (V₂T₁)

∴ V₂ = (V₁T₂)/(T₁) = (3.5 L)(313 K)/(298 K) = 3.676 L.

7 0
3 years ago
8. How many moles are in 3.01 X 10^24 of oxygen atoms?
Mademuasel [1]

Answer:

3.17

Explanation:

because u add

7 0
3 years ago
A company is interested in buying a new machine to replace their outdated equipment. However, before committing to the purchase,
klemol [59]
Efficiency is defined as the measure of the amount of work or energy is conserved in a certain process. At all times, in every process, work or energy is always lost or wasted due to certain interference. Not all work given is converted to useful work or energy. Thus , efficiency is calculated by dividing the energy or work output to the energy or work input then the value is multiplied by 100 to express efficiency as percentage.

Efficiency = work output / work input Efficiency = (1540 J / 1600 J) x 100= 96.25%
Thus, the answer is B.
3 0
3 years ago
Read 2 more answers
What can you conclude about the mass of iron (III) sulfide produced when 3.0 g of iron filings react completely with 2.5 g of ye
igor_vitrenko [27]

Answer : The mass of iron(III)sulfide is, 5.4288 g

Solution : Given,

Mass of iron, Fe = 3 g

Mass of sulfur, = 2.5 g

Molar mass of Fe = 56 g/mole

Molar mass of = 256 g/mole

Molar mass of iron(III)sulfide, = 208 g/mole

The balanced chemical reaction is,

First we have to calculate the moles of iron and sulfur.

From the balanced reaction, we conclude that

16 moles of Fe react with 3 moles of

0.054 moles of Fe react with moles of

Therefore, the excess reagent in this reaction is, Fe and limiting reagent is,

Now we have to calculate the moles of FeS.

As, 3 moles of gives 8 moles of

So, 0.0098 moles of gives moles of

The moles of = 0.0261 moles

Now we have to calculate the mass of .

Mass of = Moles of × Molar mass of

Mass of = 0.0261 g × 208 g/mole = 5.4288 g

Therefore, the mass of iron(III)sulfide is, 5.4288 g

Read more on Brainly.com - brainly.com/question/6073920#readmore

5 0
3 years ago
A chemist needs to determine the concentration of a sulfuric acid solution by titration with a standard sodium hydroxide solutio
Zigmanuir [339]

<u>Answer:</u> The concentration of original sulfuric acid solution is 1.62 M

<u>Explanation:</u>

Let the original concentration of sulfuric acid be 'x' M

To calculate the molarity of the diluted solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated sulfuric acid solution

M_2\text{ and }V_2 are the molarity and volume of diluted sulfuric acid solution

We are given:

M_1=xM\\V_1=25.00mL\\M_2=?M\\V_2=250.0mL

Putting values in above equation, we get:

x\times 25.00=M_2\times 250.0\\\\M_2=\frac{x\times 25.0}{250}=\frac{x}{10}

Now, to calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=\frac{x}{10}M\\V_1=10.00mL\\n_2=1\\M_2=0.1790M\\V_2=18.07mL

Putting values in above equation, we get:

2\times \frac{x}{10}\times 10.00=1\times 0.1790\times 18.07\\\\x=\frac{1\times 0.1790\times 18.07\times 10}{2\times 10.00}=1.62M

Hence, the concentration of original sulfuric acid solution is 1.62 M

5 0
3 years ago
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