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Katarina [22]
2 years ago
11

The rate law for a hypothetical reaction is rate = k [A][B]. If the concentrations of A and B are both 0.020 moles per liter and

k = 1.3 × 10-1 M-1s-1, what is the reaction rate?
a. 4.0 × 103 M

b. 1.3 × 10-1 M-1s-1

c. 5.2 × 10-5 Ms-1

d. 5.2 × 105 Ms-1
Chemistry
1 answer:
JulijaS [17]2 years ago
5 0
The answer is c. 5.2 * 10^-5 Ms-1. The rate law for this reaction is given. So you only need to replace the letter with number given. And also calculate the unit. Then you can get answer.
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Darya [45]
How many grams of glucose is dissolved in 2.88% glucose solution if 1944 grams of water is used???? The answer is C. 56 grams 
8 0
2 years ago
A 25 kg rock is placed in a graduated cylinder with water.the volume of the fluid is 18.3ml.calculate the density of the rock in
ipn [44]

Answer:

=> 1366.120 g/mL.

Explanation:

To determine the formula to use in solving such a problem, you have to consider what you have been given.

We have;

mass (m)     = 25 Kg

Volume (v) = 18.3 mL.

From our question, we are to determine the density (rho) of the rock.

The formula:

p = \frac{m}{v}

First let's convert 25 Kg to g;

1 Kg    = 1000 g

25 Kg = ?

= \frac{25 × 1000}{1}

= 25000 g

Substitute the values into the formula:

p =  \frac{25000 g}{18.3 ml}

= 1366.120 g/mL.

Therefore, the density (rho) of the rock is  1366.120 g/mL.

8 0
2 years ago
Based on table N of the reference tables what is the number of hours required for 42k (potassium -42) to undergo three half-life
skelet666 [1.2K]

The number of hours required : 37.2 hours

<h3>Further explanation</h3>

Given

⁴²K (potassium -42)

Required

The number of hours

Solution

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.  

Usually, radioactive elements have an unstable atomic nucleus.  

Based on Table N(attached), the half-life for ⁴²K is 12.4 hours, which means half of a sample of ⁴²K will decay in 12.4 hours

For three half-life periods :

\tt 3\times 12.4=37.2~hours

3 0
3 years ago
Find the number of CoCl2 units present in a 0.78 mol sample.
stich3 [128]

\qquad\qquad\huge\underline{{\sf Answer}}

Here we go ~

1 mole of \sf{ COCl_2} has 6.022 × 10²³ molecules of the given compound.

So, 0.78 mole of \sf{COCl_2} will have ~

\qquad \sf  \dashrightarrow \: 0.78 \times 6.022 \times 10 {}^{23}

\qquad \sf  \dashrightarrow \:  \approx4.7 \times 10 {}^{23}  \:  \:  \: molecules

5 0
2 years ago
What is the molar mass of (NH), CO?<br> 138g<br> 788<br> 968<br> 1448
aleksandr82 [10.1K]

Answer:

The molar mass of (NH_{4})_{2}CO_{3} is 96.8 g/mol

Explanation:

The given molecular formula - (NH_{4})_{2}CO_{3}

Individual molar masses of each element in the compound is as follows.

Molar mass of nitrogen - 14.01 g/mol

Molar mass of of hydrogen = 1.008g/mol

Molar mass of carbon = 12.01 g/mol

Molar mass of oxygen =16.00 g/mol

Molar mass of (NH_{4})_{2}CO_{3} is

2\times[1(14.01)+4(1.008)]+1(12.01)+3(16.00)= 96.8g/mol

Therefore,The molar mass of (NH_{4})_{2}CO_{3} is 96.8 g/mol

7 0
3 years ago
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