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Katarina [22]
2 years ago
11

The rate law for a hypothetical reaction is rate = k [A][B]. If the concentrations of A and B are both 0.020 moles per liter and

k = 1.3 × 10-1 M-1s-1, what is the reaction rate?
a. 4.0 × 103 M

b. 1.3 × 10-1 M-1s-1

c. 5.2 × 10-5 Ms-1

d. 5.2 × 105 Ms-1
Chemistry
1 answer:
JulijaS [17]2 years ago
5 0
The answer is c. 5.2 * 10^-5 Ms-1. The rate law for this reaction is given. So you only need to replace the letter with number given. And also calculate the unit. Then you can get answer.
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Answer:

pOH of resulting solution is 0.086

Explanation:

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Number of moles of OH^{-} in 375 mL of 0.88 M of KOH = \frac{0.88\times 375}{1000}moles = 0.33 moles

Number of moles of OH^{-} in 496 mL of 0.76 M of CsOH = \frac{0.76\times 496}{1000}moles = 0.38 moles

Total volume of mixture = (375 + 496) mL = 871 mL

Total number of moles of OH^{-} in mixture = (0.33 + 0.38) moles = 0.71 moles

So, concentration of OH^{-} in mixture, [OH^{-}] = \frac{0.71}{871}\times 1000M=0.82M

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2 years ago
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