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3 years ago

How many grams are in 3.8 moles of Li?

Chemistry

1 answer:

Sunny_sXe [5.5K]3 years ago

7 0

In 3.8 moles of li, there are about 0.144071459 grams. I assume that you are talking about lithium.

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Answer correctly for a brainleist! :)

RoseWind [281]

Answer:

summer

Explanation:

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3 years ago

How many moles of glucose (C6H12O6) are in 5.0 liters of a 2.5 M C6H12O6 solution?

zhannawk [14.2K]

N = M x V

n = 2.5 x 5.0

n = 12.5 moles of C6H12O6

5 0

3 years ago

A buffer is a solution that is a mixture of either a weak acid and its conjugate base or a weak base and its conjugate acid. Whe

leva [86]

Answer:

a. The conjugate base of an acidic buffer will accept hydrogen protons when a strong acid is added to the solution.

b. An acidic buffer solution is a mixture of a weak acid and its conjugate base.

e. The weak acid of an acidic buffer will donate hydrogen protons when a strong base is added to the solution.

Explanation:

Which of the statements correctly describe the properties of a buffer?

a. The conjugate base of an acidic buffer will accept hydrogen protons when a strong acid is added to the solution. TRUE. The conjugate base neutralizes the excess of hydrogen protons.

b. An acidic buffer solution is a mixture of a weak acid and its conjugate base. TRUE.

c. An acidic buffer solution is a mixture of a weak base and its conjugate acid. FALSE. This is a basic buffer solution.

d. The weak acid of an acidic buffer will accept hydrogen protons when a strong base is added to the solution. FALSE. The weak acid will react with the hydroxyl ions from the added base.

e. The weak acid of an acidic buffer will donate hydrogen protons when a strong base is added to the solution. TRUE. These hydrogen protons will form water.

f. The conjugate base of an acidic buffer will donate hydrogen protons when a strong acid is added to the solution. FALSE. It will accept hydrogen protons.

7 0

3 years ago

Why do some substances react with each other while others do not

kolbaska11 [484]

It depends on the Chemical the Substance has. The more Chemicals, the better the Substance gets when its mixed with another.

7 0

3 years ago

A volume of 80.0 mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. I

murzikaleks [220]

Answer:

The mass of the steel bar is 26.833 grams

Explanation:

Step 1: data given

ΣQ gained = ΣQ lost

Q=m*C*ΔT

with m = mass in grams

with C= specific heat capacity ( in J/(g°C))

with ΔT = change in temperature = T2-T1

Qsteel = Qwater

msteel * Csteel * (T2steel - T1steel) = mwater * Cwater * (T2water - T1water)

Mass of steel = TO BE DETERMINED

mass of water =⇒ since 1mL = 1g : 80 mL = 80g

Csteel =0.452 J/(g °C

Cwater = 4.18 J/(g °C

initial temperature steel T1 : 2 °C

final temperature steel T2 = 21.3 °C

initial temperature water T1 =22 °C

final temperature water T2 = 21.3 °C

Step 2: Calculate mass of steel

msteel * Csteel * (T2steel - T1steel) = mwater * Cwater * (T2water - T1water)

msteel * 0.452 *(21.3-2) = 80 * 4.18 * (21.3-22)

msteel = (80 * 4.18 * (-0.7)) / (0.452 * 19.3)

msteel = -234.08 / 8.7236

msteel = -26.833 g

Since mass can't be negative we should take the absolute value of it = 26.833g

The mass of the steel bar is 26.833 grams

6 0

3 years ago