Answer:
1/2
Step-by-step explanation:
Hi Avahosel2020!
To find the value of
we need to simplify the equation:
25
= 12.5
To just get
, we must divide 25 on both sides:
= 
<u>We can move the decimal one spot over and add a 0 to the denominator:</u>
= 
= 
Simplifying!
=
.
Thus,
has the value of
.
Answer:

Step-by-step explanation:
Before we find x, we need to set up this triangle a little more. We need to find the triangle's altitude before we can solve for x. We will use the heartbeat method to find the altitude.
Let altitude = y; solve for y:




Now that we know the altitude, we can use the Pythagorean Theorem to find the hypotenuse (x).





Since c and x are the same; c is just the hypotenuse in the Pythagorean Theorem.

(5,4)
On a system of 2 perpendicular axis with O as origine, the pair (5,4) means:
5 is the distance from the origin O and situated on x-axis (on the right of O)
4 is the distance from the origin O and situated on y-axis (above O)
Then the pair (5,4) is situated in the 1st Quadrant
<u>Answer</u>:- No.
<u>Explanation</u> :-
<u>Substitute these numbers in pythagoras theorem to check if the set of numbers is a pythagorean triplet.</u>
<u>Pythagoras theorem</u> :- sq. of hypotenuse (longest side) is equal to the sum of sq.s of other two sides.
<u>Here</u>,
hypotenuse = 12 (as it is the longest side)
and other two sides are 6 and 9.
----> 6^2 + 9^2 = 12^2
----> 36 + 81 = 144
----> 117 = 144
Since, LHS is not equal to RHS, this set of numbers is not a pythagorean triplet.