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gulaghasi [49]
3 years ago
10

I really need help on geometry

Mathematics
1 answer:
balu736 [363]3 years ago
8 0
For example, exc. 15.

x + y = 10 and 6/x = 9/y; You need y!

=> x = 10 -y and 9x = 6y => 9(10-y) = 6y => 90 - 9y = 6y => 15y = 90 => y = 6.
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The ratio of the area of a circle, P , to the area of another circle, Q , is 16/81 .
stellarik [79]
Ratio of  the radii = sqrt16 / sqrt81 = 4/9

so radius of circle Q  is  found by solving  4/9 = 8/x  where x = radius of Q

x = 2*9  = 18

radius of circle Q = 18.
6 0
3 years ago
Two lines, R and M, are represented by the following equations:
Katena32 [7]
If you would like to know what is true about the solution of the set of equations, you can calculate this using the following steps:

2x + 2y = 18
x + y = 9    /*2
______________

<span>2x + 2y = 18
</span>2x + 2y = 18
______________
2x + 2y = <span>2x + 2y
</span>18 = 18
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The correct result would be infinitely many solutions.
8 0
3 years ago
What's the answer someone pleaseeeee tell me
den301095 [7]
Number three is 80
Number three is 150
5 0
3 years ago
PLS HELP ITS URGENT!
love history [14]

Answer:

the slope is 3

Step-by-step explanation:

8 0
2 years ago
What is the perimeter of the triangle shown on the coordinate plane,to the nearest tenth of a unit ?
ollegr [7]

Answer:

25.6 units

Step-by-step explanation:

From the figure we can infer that our triangle has vertices A = (-5, 4), B = (1, 4), and C = (3, -4).

First thing we are doing is find the lengths of AB, BC, and AC using the distance formula:

d=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}

where

(x_1,y_1) are the coordinates of the first point

(x_2,y_2) are the coordinates of the second point

- For AB:

d=\sqrt{[1-(-5)]^{2}+(4-4)^2}

d=\sqrt{(1+5)^{2}+(0)^2}

d=\sqrt{(6)^{2}}

d=6

- For BC:

d=\sqrt{(3-1)^{2} +(-4-4)^{2}}

d=\sqrt{(2)^{2} +(-8)^{2}}

d=\sqrt{4+64}

d=\sqrt{68}

d=8.24

- For AC:

d=\sqrt{[3-(-5)]^{2} +(-4-4)^{2}}

d=\sqrt{(3+5)^{2} +(-8)^{2}}

d=\sqrt{(8)^{2} +64}

d=\sqrt{64+64}

d=\sqrt{128}

d=11.31

Next, now that we have our lengths, we can add them to find the perimeter of our triangle:

p=AB+BC+AC

p=6+8.24+11.31

p=25.55

p=25.6

We can conclude that the perimeter of the triangle shown in the figure is 25.6 units.

6 0
3 years ago
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