1 gram = 1000 milligrams
/ move the decimal to the left 3 because you multiply by 10^3
5.712 grams = 5,712 milligrams
1 gram = 0.001 kilograms
/ move decimal to the right 3 because you multiply by 10^ -3
5.712 grams = 0.005712 kilograms
Answer:
accuracy
Explanation:
Accuracy refers to the closeness of the accepted value
Precision refers to the closeness of the measurements to each other
Answer:
the change in the system internal energy is 20 J
Explanation:
The computation of the change in the system internal energy is as follows:
Since the volume remains constant so the work done would be zero
Now the change in the internal energy is
= Heat given to system - work done
= 20 J - 0
= 20 J
hence, the change in the system internal energy is 20 J
The same is to be considered
Explanation:
The conversion of the liquid to the vapor below boiling temperature of liquid is called evaporation.
Each molecule in liquid phase is attracted to other molecules in liquid by the intermolcular forces of attraction. When the process of evaporation starts, the molecules has to change the phase from the liquid to vapor for which they have to break all these interaction so that they can escape. The molecules with sufficient energy to do so only can do this. These molecules with high energy leave and remaining molecules are ones which did not have the enough energy to evaporate. Thus, average kinetic energy of molecules in liquid left behind is lower than it was before. <u>So, evaporation is a cooling process because heat of the molecules was used up for breaking hotter molecules out into gas phase and the left ones are cooled.
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Answer:
<em>The correct option is C) The number of collisions of gas particles decreases</em>
Explanation:
The molecules in a gas are not located close to each other as molecules in a solid or a liquid. The molecules in a gas have more energy. If we decrease the number of particles in a gas, then there will be reduced collisions as the molecules are already located further apart.
However, a decrease in the volume will affect the pressure of a gas, not the decrease in the number of gas particles.