Answer:
Energy per mole of photons = 2.31 × 10^2 KJ/mol
Explanation:
Energy, E = hf;
Where h is Planck's constant = 6.63 ×10^-34, and f is frequency of the photons.
E = 6.63 × 10^-34 × 5.8 × 10^14
E = 3.84 × 10^-22 KiloJoules
I mole of photons contains Avogadro's number of particles, 6.02 × 10^23
Therefore, the energy per mile of photon is 3.84 × 10^-22 KJ × 6.02 × 10^23
Energy per mile of photon = 2.31 × 10^2 KJ/mol
Ok so first you need to figure out the energy of ONE photon with that wavelength. Using E=hc/lambda, you get E= 1.99 * 10^-20 J/photon. Now, how many photons do you need to add up to get to one kilojoule=1000 joules? 1000J / (1.99 * 10^-20 J/photon) = approximately 5 * 10^22 photons
hope this helps
Answer:
Explanation:
Here, we want to calculate the number of moles of methane in the container
From the ideal gas law:
where:
P is the pressure inside the container which is 3 atm
V is the volume of the container which is 2 L
R is the molar gas constant which is 0.0821 Latm/mol.k
T is the temperature in Kelvin (we convert the temperature in Celsius by adding 273 : 273 + 77 = 350 K)
n is the number of moles that we want to calculate
Substituting the values, we have it that:
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