Maya has an attached earlobe. What is responsible for Maya’s ear shape?

Dioxin is a by-product of various industrial chemical processes. It is suspected of causing cancer and birth defects in both hum

Nuetrik [128]

Answer:

The natural ligand of the cytosolic Aryl hydrocarbon receptor which is still not known.

Explanation:

Dioxin is formed during some industrial chemical processes. It is considered harmful because it causes cancer, weakens the immune system, results in nervous breakdown and also affects reproduction.

The mechanism of operation of Dioxins has not been fully understood. However, it is known that dioxins works through a receptor known as the Aryl hydrocarbon receptor. This receptor is useful in gene expression and also acts as a transcription factor.

4 0

2 years ago

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[Send a message] as you move across a row from left to right in the period table, atomic numbers of the elements

SashulF [63]

I think it might be D or B
And my other two might be A or C

6 0

3 years ago

A ____ is the remains of a once-living organism found in layers of rocks, ice, or amber

aksik [14]

Answer:

fossil

Explanation:

the dead organism is called a fossil i think

8 0

2 years ago

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Calculate the average bond order for a p−o bond (such as the one shown in blue) in a phosphate ion. express your answer numerica

PtichkaEL [24]

<span>Answer: 1/4 is the average bond order for a pâ’o bond (such as the one shown in blue) in a phosphate ion.</span>

5 0

3 years ago

The reaction 2NO(g)+O2(g)−→−2NO2(g) is second order in NO and first order in O2. When [NO]=0.040M, and [O2]=0.035M, the observed

Oksanka [162]

Answer:

(a) The rate of disappearance of $O_{2}$ is: $4.65*10^{-5}$ M/s

(b) The value of rate constant is: 0.83036 $M^{-2}s^{-1}$

(c) The units of rate constant is: $M^{-2}s^{-1}$

(d) The rate will increase by a factor of 3.24

Explanation:

The rate of a reaction can be expressed in terms of the concentrations of the reactants and products in accordance with the balanced equation.

For the given reaction:

$2NO(g)+O_{2}->2NO_{2}$

rate = $-\frac{1}{2} \frac{d}{dt}[NO]$ = $-\frac{d}{dt}[O_{2}]$ = $\frac{1}{2}\frac{d}{dt}[NO_{2}]$ -----(1)

According to the question, the reaction is second order in NO and first order in $O_{2}$ .

Then we can say that, rate = k $[NO]^{2}[O_{2}]$ -----(2)

where k is the rate constant.

The rate of disappearance of NO is given:

$-\frac{d}{dt}[NO]$ = $9.3*10^{-5}$ M/s.

(a) From (1), we can get the rate of disappearance of $O_{2}$ .

Rate of disappearance of $O_{2}$ = $-\frac{d}{dt}[O_{2}]$ = (0.5)*( $9.3*10^{-5}$ ) M/s = $4.65*10^{-5}$ M/s.

(b) The rate of the reaction can be obtained from (1).

rate = $-\frac{1}{2} \frac{d}{dt}[NO]$ = (0.5)*( $9.3*10^{-5}$ )

rate = $4.65*10^{-5}$ M/s

The value of rate constant can be obtained by using (2).

rate constant = k = $\frac{rate}{[NO]^{2}[O_{2}]}$

k = $\frac{4.65*10^{-5}}{(0.040)^{2}(0.035)}$ = 0.83036 $M^{-2}s^{-1}$

(c) The units of the rate constant can be obtained from (2).

k = $\frac{rate}{[NO]^{2}[O_{2}]}$

Substituting the units of rate as M/s and concentrations as M, we get:

$\frac{Ms^{-1} }{M^{3}}$ = $M^{-2}s^{-1}$

(d) The reaction is second order in NO. Rate is proportional to square of the concentration of NO.

$rate\alpha [NO]^{2}$

If the concentration of NO increases by a factor of 1.8, the rate will increase by a factor of $(1.8)^{2}$ = 3.24

5 0

3 years ago