Hi,
This change is physical because there is no new formation of a new substance or any signs of a chemical change, only the physical properties change.
Answer:
Explanation:
Hello,
In this case, we can compute the the freezing point depression by using the following formula:
Whereas the freezing point of pure water is 0 °C van't Hoff factor for glucose is 1, the molality is computed as shown below and the freezing point constant of water is 1.86 °C/m:
Thus, the freezing point of the solution is:
Regards.
If a sample of gas is a 0.622-gram, volume of 2.4 L at 287 K and 0.850 atm. Then the molar mass of the gas is 7.18 g/mol
<h3>What is an ideal gas equation?</h3>
The ideal gas law (PV = nRT) relates to the macroscopic properties of ideal gases.
An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
Given :
The ideal gas equation is given below.
n = PV/RT
n = 86126.25 x 0.0024 / 8.314 x 287
n = 0.622 / molar mass (n = Avogardos number)
Molar mass = 7.18 g
Hence, the molar mass of a 0.622-gram sample of gas having a volume of 2.4 L at 287 K and 0.850 atm is 7.18 g
More about the ideal gas equation link is given below.
brainly.com/question/4147359
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From the stoichiometry of the problem, 2.01 × 10^5 g of zinc phosphate is produced.
<h3>What is volume?</h3>
Volume is the product of width, height and depth. The significant figures of the width, height and depth are 5, 4 and 6 respectively.The volume of the box is; 11.014 × 10^-2 m × 0.2481 m × 523.735 × 10^-3 = 0.01431 m^3 or 14310 cm^3 or 0.5053ft^3.
Density of zinc = 7.140 g / cm3
Volume of zinc = 14310 cm^3
Mass of zinc = 7.140 g / cm3 × 14310 cm^3 = 102 Kg
Moles of Zinc = mass /molar mass = 102 × 10^3/65 g/mol = 1569 moles
There are 195 g of zinc in 386 g zinc phosphate
102 × 10^3 g of Zn will produce x g
x = 102 × 10^3 g × 386 g / 195 g
x = 2.01 × 10^5 g of zinc phosphate
Learn more about stiochiometry: brainly.com/question/9743981
