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3 years ago

The hydrogenation of unsaturated hydrocarbons is

Chemistry

1 answer:

Ann [662]3 years ago

6 0

Answer:

The metal catalyst in catalytic hydrogeation process increases the rate of reaction by lowering the activation energy of the reaction, by allowing the reaction take place at a much lower temperature than it would have without the metl ctalyst.

This catalysis is regarded as heterogeneous or surface catalysis.

Explanation:

The hydrogen is first bonded to the metallic powder as the initial step of the reaction.

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Draw the Lewis structure for NF3. What orbitals on N and F overlap to form bonds between these elements

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2 years ago

The reaction for photosynthesis producing glucose sugar and oxygen gas is:

Anvisha [2.4K]

1.5 grams of glucose is produced from 2.20 g of CO₂.

To find the mass of glucose produced, first you must know the balanced reaction. For this, the Law of Conservation of Matter is followed.

The law of conservation of matter states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.

So, in this case, the balanced reaction is:

6 CO₂ + 6 H₂O → C₆H₁₂O₆ + 6 O₂

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the amounts of moles of each reactant and product participate in the reaction:

CO₂: 6 moles
H₂O: 6 moles
C₆H₁₂O₆: 1 mole
O₂: 6 moles

So, you know that 2.20 g of CO₂ react, whose molar weight is 44.01 g/mole. By definition of molar mass, 1 mole of CO₂ has 44.01 g. So, the number of moles that 2.20 grams of the compound represent is calculated as:

$moles of CO_{2} =2.20 grams*\frac{1 mole}{44.01 grams}$

moles of CO₂= 0.05 moles

Now you must follow the following rule of three: if by stoichiometry of the reaction 6 moles of CO₂ produce 1 mole of C₆H₁₂O₆, 0.05 moles of CO₂ produce how many moles of C₆H₁₂O₆?

$moles of C_{6} H_{12} O_{6} =\frac{0.05moles of CO_{2} *1 mole of C_{6} H_{12} O_{6}}{6moles of CO_{2}}$

moles of C₆H₁₂O₆= 8.33*10⁻³

Being the molar mass of glucose 180.18 g/mole, the mass that 8.33*10⁻³ moles of the compound represent is calculated as:

$mass of glucose =8.33*10^{-3} moles*\frac{180.18 grams}{1 mole}$

mass of glucose= 1.5 grams

Then, 1.5 grams of glucose is produced from 2.20 g of CO₂.

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3 years ago

What is the approximate pressure of a storage cylinder of recovered R-404A that does not contain any non-condensable impurities

gregori [183]

Answer:

288 psig

Explanation:

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3 years ago

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What is the correct name of the compound Mn3(PO4)2? A. manganese phosphate B. manganese(I) phosphate C. manganese(III) phosphate

Sergio039 [100]

The correct name of the compound Mn3(PO4)2 is definitely the last option represented above D. manganese(II) phosphate. I am pretty sure this answer will help you

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3 years ago

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lana66690 [7]

1. C

2. C

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I hope this helped :D

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3 years ago