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cupoosta [38]
3 years ago
12

Which part of the microscope should be used with the low-power objective, but not the high power objective?

Chemistry
1 answer:
slamgirl [31]3 years ago
7 0

Answer: 1

Explanation: coarse adjustment

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If distance, d, is proportional to time, t, and at time t =2.00 seconds, the distance is 6.20 m, find the distance when t = 3.50
Allushta [10]
At 3.5s the distance would be 10.85

Find 1/4th of 2.00 and add that to 6.2
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In the equation KClO3 -> KCl + O2, how many moles of oxygen are produced when 3.0 mol of KClO3 decomposes completely?
IceJOKER [234]

Answer:

4.5

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3 years ago
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Sulfur is a nonmetalic mineral that has a density of 2 g/cm3. The volume of a sample of sulfur was measured to be 5.0 cm3. what
taurus [48]

Answer:

<h2>10 g</h2>

Explanation:

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mass = Density × volume

From the question we have

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<h3>10 g</h3>

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8 0
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Ponds and rivers are two types of
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<u><em>Ponds and rivers are two types of  . . . . freshwater ecosystems</em></u>
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3 years ago
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Calculate the energy of one photon of yellow light that has a wavelength of 5.89x10^-7m.​
Viktor [21]

Answer:

E = energy = ? ,

λ = Wavelength = 5.89 × 10^-7 m —> = 589 ×10 ^-9 m ,

h =Planck constant = 6.63 × 10^-34 J.s ,

f = frequency of photo/ electromagnetic radiation = c/λ ,

c = Speed of light in a vacuum = 3 × 10^8 m/s

___o___o____

E = hf \\  \\ E = h \frac{c}{λ}  \\  \\  E = 6.63 \times  {10}^{ - 34}  \frac{3 \times  {10}^{8} }{5.89 \times  {10}^{ - 7} }  \\  \\E =  \frac{6.63 \times  {10}^{ - 34} \times 3 \times  {10}^{8}  }{5.89 \times  {10}^{ - 7} }   \\  \\ E =  \frac{663 \times  {10}^{ - 36} \times 3 \times  {10}^{8}  }{589 \times  {10}^{ - 9} }  \\  \\ E =  \frac{1989 \times  {10}^{ - 28} }{589 \times  {10}^{ - 9} }  \\  \\ E = 3.37691 \times  {10}^{ - 19} J

I hope I helped you^_^

8 0
3 years ago
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