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cupoosta [38]
3 years ago
12

Which part of the microscope should be used with the low-power objective, but not the high power objective?

Chemistry
1 answer:
slamgirl [31]3 years ago
7 0

Answer: 1

Explanation: coarse adjustment

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Please help with these asap
aleksklad [387]

14. a. Acidic

15. b. Weaker

16. d. Dilute and weak

Explanation:

14. Which type of the solution is one with the pH of 3?

Solution with pH from 1 to 7 are acidic, equal to 7 is neutral and from 7 to 14 basic. The solution with the pH equal to 3 is <u>acidic</u>.

15. The smaller the value of the base dissociation constant (Kb), the <u>weaker</u> the base.

The dissociation reaction of a base (B) is:

B + H₂O → BH⁺ + OH⁻

Kb is defined as:

Kb = ( [BH⁺] × [OH⁻] ) / ( [B] × [H₂O] )

The potency of the base depends on the concentration of the hydroxide ion [OH⁻], so if the Kb ratio is small it means that the concentration of hydroxide ion is smaller so the base will be <u>weaker</u>.

16. A 0.39 M solution of an acid that ionizes only slightly in solution would be termed <u>dilute and weak</u>.

The acid is weak because is only slightly ionizing in solution. The therm diluted is a little bit arbitrarily because we ask yourself "diluted in respect with what"? I would characterize the acid to be diluted at a concentration of 1 M and concentrated at a concentration of 10 M.

Learn more about:

pH

brainly.com/question/1402522

#learnwithBrainly

8 0
3 years ago
Determine the molar concentration of na+ and po4 3- in a 2.25 M Na3 PO4 solution
muminat

Answer:

A. The concentration of Na^+ in the solution is 6.75 M.

B. The concentration of PO4^3- in the solution is 2.25 M.

Explanation:

We'll begin by writing the balanced dissociation equation for Na3PO4.

This is illustrated below:

Na3PO4 will dissociate in solution as follow:

Na3PO4(aq) —> 3Na^+(aq) + PO4^3-(aq)

Thus, from the balanced equation above,

1 mole of Na3PO4 produce 3 moles of Na^+ and 1 mole of PO4^3-

A. Determination of the concentration of Na+ in 2.25 M Na3PO4 solution.

This can be obtained as follow:

From the balanced equation above,

1 mole of Na3PO4 produce 3 moles of Na^+.

Therefore, 2.25 M Na3PO4 solution will produce = (2.25 x 3) /1 = 6.75 M Na^+.

Therefore, the concentration of Na^+ in the solution is 6.75 M

B. Determination of the concentration of PO4^3- in 2.25 M Na3PO4 solution.

This can be obtained as follow:

From the balanced equation above,

1 mole of Na3PO4 produce 1 mole of PO4^3-

Therefore, 2.25 M Na3PO4 solution will also produce 2.25 M PO4^3-.

Therefore, the concentration of PO4^3- in the solution is 2.25 M.

7 0
3 years ago
Which of the following is NOT a reason for the experimental volume of the flask to be incorrect?
dsp73

Answer:

2

Explanation:

i dont andesdant

4 0
3 years ago
Solve the quadratic equation 2x^2+13x=15 by method of completing the square<br>​
mafiozo [28]

Answer:

x = 1, -7.5

Explanation:

2x² + 13x = 15

Divide the left side of the equation by 2

2(x² + 6.5x) = 15

Divide 6.5 by 2 and square the quotient

6.5/2 = 3.25

3.25² = 10.5625

Add 10.5625 to the left side

2(x² + 6.5x + 10.5625) = 15

Since you have a 2 outside the parentheses, you will be adding 10.5625•2 to the right side.

10.5625 • 2 = 21.125

2(x² + 6.5x + 10.5625) = 36.125

To factor (x² + 6.5x + 10.5625), add b/2 to x

b/2 = 6.5/2 = 3.25

2(x + 3.25)² = 36.125

Divide by 2

(x + 3.25)² = 18.0625

Square root.

(x + 3.25) = √18.0625

x + 3.25 = ±4.25

Subtract 3.25.

x = 4.25 - 3.25 = 1

x = -4.25 - 3.25 = -7.5

x = 1, -7.5

4 0
3 years ago
Write a molecular equation for the gas-evolution reaction that occurs when you mix aqueous hydroiodic acid and aqueous sodium su
Leona [35]
First, we construct the reaction equation:

Na₂SO₃ + 2HCl → 2NaCl + SO₂ + H₂O

H₂SO₃ is formed as an intermediate but decomposes to water and SO₂ gas.
6 0
3 years ago
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