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matrenka [14]
4 years ago
6

at time t, in hours, a lake is covered with ice of thickness y cm, where y = .5 t^1.5 . if ice forms for 0 <= t <= 6, at w

hat time in this interval is the ice thickest? at what time is the ice forming fastest?
Mathematics
1 answer:
andriy [413]4 years ago
5 0
Y = .5 * t^(1.5)
Points on the graph are:
( 0, 0 ) , ( 1 , .5 ), ( 2 1.41 ), ( 3, 2.5985 ), ( 4 , 4 ), ( 5 , 5.59 ) , ( 6, 7.34 ).
Answer:
The ice is thickest at t = 6.
The ice is forming fastest at t = 6. 
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Since we have a total of 8 locations ( 4 to the new ointment and 4 to the control) ,  each one can be chosen and since the order of the locations that are chosen for the new ointment is not relevant  , then we know that the number of choices is given by the number of combinations of 4 elements in 8

number of combinations = 8 possible locations to the first ointment * 7 possible locations to the second ( since the first one was already located) * 6 to the third * 5 locations for the fourth / number of times the same combination is repeated ( the same locations but in different positions) = 8*7*6*5 / (4 possible positions for the first ointment* 3 possible positions to the second ointment (since the first one was already located * 2 possible positions of the third * 1 possible position of the fourth)

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