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3 years ago

7

For what value of x would the quotient (2x^2+3x-4) divided (x=4) not make sense ??

1 answer:

ra1l [238]3 years ago

8 0

Plug in 4 for X and you get 44

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Find the slope of the line whose equation is 7x - 2y = 4.<br> -2<br> 7/2<br> 4/7

sesenic [268]

Answer: 7/2

To find the slope, we must put the equation in y = mx + b form, and m represents ur slope.

7x - 2y = 4....subtract 7x from both sides
-2y = -7x + 4 ...now divide both sides by -2
y = (-7/-2)x + (4/-2)
y = 7/2x - 2....now we have it in y = mx + b form, and since m is ur slope, ur slope in this equation is 7/2.

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3 years ago

In the above bridge, line segment BD is the perpendicular bisector of line segment AC. For the bridge to be safe, Triangle ABD i

klasskru [66]

Answer: we can get the sequence of reasons with help of below explanation.

Step-by-step explanation:

Here It is given that, line segment BD is the perpendicular bisector of line segment AC. ( shown in below diagram)

By joining points B with A and B with C ( Construction)

We get two triangles ABD and CBD.

We have to prove that : Δ ABD ≅ Δ CBD

Statement Reason

1. AD ≅ DC 1. By the property of segment bisector

2. ∠BDA ≅ ∠ BDC 2. Right angles

3. BD ≅ BD 3. Reflexive

4. Δ ABD ≅ Δ CBD 4. By SAS postulate of congruence

8 0

3 years ago

Help.........................<br><br>

garri49 [273]

<h3>Answer: Choice A</h3>

$x^2\left(\sqrt[4]{x^2}\right)$

=====================================================

Explanation:

The fourth root of x is the same as x^(1/4)

I.e,

$\sqrt[4]{x} = x^{1/4}$

The same applies to x^10 as well

$\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4}$

Multiply the exponents 10 and 1/4 to get 10/4

$\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4} = x^{10*1/4} = x^{10/4}$

$\sqrt[4]{x^{10}} = x^{10/4}$

-----------------------

If we have an expression in the form x^(m/n), with m > n, then we can simplify it into an equivalent form as shown below

$x^{m/n} = x^a\sqrt[n]{x^b}$

The 'a' and 'b' are found through dividing m/n

m/n = a remainder b

'a' is the quotient, b is the remainder

-----------------------

The general formula can easily be confusing, so let's replace m and n with the proper numbers. In this case, m = 10 and n = 4

m/n = 10/4 = 2 remainder 2

We have a = 2 and b = 2

So

$x^{m/n} = x^a\sqrt[n]{x^b}$

turns into

$x^{10/4} = x^2\sqrt[4]{x^2}$

which means

$\sqrt[4]{x^{10}} = {x^2} \sqrt[4]{x^2}$

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3 years ago

A right rectangular pyramid is sliced parallel to the base, as shown.

Natali5045456 [20]

#1 15cm^2. ====> Good Luck! <====

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3 years ago

What do you have to do to each side to solve 5x < 20? <br> Solve 5x < 20. ✏️Show your work

sergejj [24]

Answer:

x < 4

Step-by-step explanation:

Step 1: Write inequality

5x < 20

Step 2: Solve for <em>x</em>

Divide both sides by 5: x < 4

Here we see that any number less than 4 will work. So numbers like 3, 0, or even -12587235897 would work.

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3 years ago