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Zielflug [23.3K]
3 years ago
11

Help please don’t answer if you don’t know also I’ll give give out brainliest order of operation

Mathematics
2 answers:
IgorC [24]3 years ago
7 0

Answer:55

your welcome

Naddika [18.5K]3 years ago
3 0

Answer:

55

Step-by-step explanation:

1. Add

2. divide

3. multipy

4. subtract

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Consider the linear function that is represented by the equation y = 2 x + 2 and the linear function that is represented by the
frutty [35]

Answer:

C) the function represented by the graph has a steeper slope and the function represented by the equation has a larger y-intercept.

Step-by-step explanation:

The equation is written in slope-intercept form, y=mx+b.  m is the slope and b is the y-intercept.  In this function, the slope is 2 and the y-intercept is 2.

Looking at the graph, the y-intercept is 1.  Going from the y-intercept, if we go up 2, it does not go over quite 1 unit.  Therefore the slope is steeper on the graph.

Hope I helped answer the question:)

3 0
3 years ago
How can you solve an equation with a variable on both sides
Ne4ueva [31]
It depends. You'd need to give some example, but generally the idea is to put all variables on one side and everything else on the other side.

15 +2x =2+5x\\
2x-5x=2-15\\
-3x=-13\\
x=\dfrac{13}{3}
8 0
3 years ago
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I need help solving this please
Kruka [31]
I really hope this helps this is what my teacher said to do in the type of problem

7 0
3 years ago
Hola necesito ayuda con esta pregunta:
Svetradugi [14.3K]
Okay it’s the right answer
4 0
3 years ago
What is the perimeter of the triangle shown on the coordinate plane,to the nearest tenth of a unit ?
ollegr [7]

Answer:

25.6 units

Step-by-step explanation:

From the figure we can infer that our triangle has vertices A = (-5, 4), B = (1, 4), and C = (3, -4).

First thing we are doing is find the lengths of AB, BC, and AC using the distance formula:

d=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}

where

(x_1,y_1) are the coordinates of the first point

(x_2,y_2) are the coordinates of the second point

- For AB:

d=\sqrt{[1-(-5)]^{2}+(4-4)^2}

d=\sqrt{(1+5)^{2}+(0)^2}

d=\sqrt{(6)^{2}}

d=6

- For BC:

d=\sqrt{(3-1)^{2} +(-4-4)^{2}}

d=\sqrt{(2)^{2} +(-8)^{2}}

d=\sqrt{4+64}

d=\sqrt{68}

d=8.24

- For AC:

d=\sqrt{[3-(-5)]^{2} +(-4-4)^{2}}

d=\sqrt{(3+5)^{2} +(-8)^{2}}

d=\sqrt{(8)^{2} +64}

d=\sqrt{64+64}

d=\sqrt{128}

d=11.31

Next, now that we have our lengths, we can add them to find the perimeter of our triangle:

p=AB+BC+AC

p=6+8.24+11.31

p=25.55

p=25.6

We can conclude that the perimeter of the triangle shown in the figure is 25.6 units.

6 0
3 years ago
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