<u>Given:</u>
Enthalpy change (ΔH) for SO3 decomposition = +790 kJ
Moles of SO3 = 2.1 moles
<u>To determine:</u>
Energy required when 2.1 moles of SO3 reacts
<u>Explanation:</u>
The decomposition reaction is -
2SO3(g) → 2S(s) + 3O2 (g)
Energy required when 2 moles of SO3 reacts is 790 kJ
Thus, for 2.1 moles of SO3 the energy requirement would be
= 2.1 moles SO3 * 790 kJ/2 moles SO3 = 829.5 kJ
Ans: 830 kJ are required when 2.1 moles of SO3 reacts.
When the person said"nuke it" they are not referring to what they are going to nuke. That is why it is incorrect.
Answer:
In 1 mole of HCl is 36,46 grams
Explanation:
Molar mass of HCl = 1,01 (H) + 35,45 (Cl) = 36,46 g/mole
We use the formula n=m/M to calculate the mass
1 mole = m/ 36,46g/mol
mass = 36,46g/mole* 1 mole = 36,46 grams