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3 years ago

The two main classes of mixtures are

Chemistry

2 answers:

Slav-nsk [51]3 years ago

4 0

Explanation:

Mixtures are the substances that contain two or more atoms mixed together in different composition.

There are two main classes of mixtures which are as follows.

Homogeneous mixtures - These are the mixtures in which solute particles are uniformly distributed into the solvent.

For example, NaCl when dissolved in water forms a homogeneous solution.

Heterogeneous mixture - These are the mixtures in which solute particles are non-uniformly distributed into the solvent.

For example, sand mixed in water is a heterogeneous solution.

Vesnalui [34]3 years ago

3 0

Homogeneous or heterogeneous, Hope this helps!!

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Choose the products that complete the reaction NaHCO3+HC2H3O2

Novosadov [1.4K]

Answer:

The products will be;

CO₂ + H₂O + NaC₂H₃O₂

Explanation:

We are given;

Two reactants NaHCO₃ and HC₂H₃O₂

We are supposed to determine the products;

We need to know that hydrogen carbonates reacts with acids to give water, carbon dioxide and a salt as the products.

Therefore;

In this case, sodium hydrogen carbonates (baking soda) reacts with acetic acid to form water, carbon dioxide and sodium acetate.
The equation for the reaction is;

NaHCO₃ + HC₂H₃O₂ → CO₂ + H₂O + NaC₂H₃O₂

Therefore, the products of the complete reaction between sodium hydrogen carbonate and acetic acid are CO₂ + H₂O + NaC₂H₃O₂

3 0

3 years ago

Equilin is an estrogen isolated from the urine of pregnant mares. The percent composition of equilin is 80.56 percent C, 7.51 pe

tatuchka [14]

Answer:

The correct answer is C18H20O2.

Explanation:

Based on the given information, one hundred grams of equilin contains 80.56% Carbon, 7.51% Hydrogen, and 11.95% Oxygen. Thus, by mass it comprises 80.56 g Carbon, 7.51 g Hydrogen, and 11.92 g Oxygen.

The molecular mass of carbon, hydrogen, and oxygen are 12.01 g/mol, 1.008 g/mol, and 16.00 g/mol.

The moles of the elements present can be determined by using the formula,

Moles = Weight/Molecular mass

Moles of C = 80.56 g/12.01 g/mol = 6.708 mol

Moles of H = 7.51 g/1.008 g/mol = 7.45 mol

Moles of O = 11.92 g/16 g/mol = 0.745 mol

This gives the formula of C6.708H7.45O0.745. By dividing the subscripts from the smallest value, the possible whole numbers obtained will be,

6.708/0.745 = 9, 7.45/0.745 = 10, 0.745/0.745 = 1. Now the empirical formula obtained will be, C9H10O

Now dividing the molar mass of equilin, that is, 268 g/mol from the empirical formula mass, that is, 9*12.01 g/mol + 10*1.008 g/mol+ 16.00 g/mol = 134.2 g/mol, we get,

268/134.2 = 2

Now by multiplying the subscripts in the empirical formula with 2, the molecular formula obtained will be,

C18H20O2.

6 0

3 years ago

Does it take more, less, or the same amount of heat to melt 1.0 kg of ice at 0°C, or to bring 1.0 kg of liquid water at 0°C to t

Murljashka [212]

Answer : It takes less amount of heat to metal 1.0 Kg of ice.

Solution :

The process involved in this problem are :

$(1):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(2):H_2O(l)(0^oC)\rightarrow H_2O(l)(100^oC)$