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4 years ago

What mass of helium is in a 2.00L ballon at STP

Chemistry

1 answer:

MAXImum [283]4 years ago

6 0

Answer:

0.357 g He

Explanation:

1 mol of gas at STP = 22.4 L

2.00 L * 1 mol/22.4 L = 0.08929 mol He

M(He) = 4.00 g/mol

0.08929 mol He * 4.00 g/ 1 mol He = 0.357 g He

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3 years ago

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3 years ago

Calculate the mass of gold (0.130 J/g°C) that requires 468 J to heat the metal from 21.6 °C to 33.2 °C?

Lemur [1.5K]

Answer:

The mass of gold is found to be 310.34 g.

Explanation:

We have:

Specific heat of gold = C = 0.130 J/g.°C

Heat = H = 468 J

Change in Temperature = ΔT = 33.2 °C - 21.6 °C = 11.6 °C

Now, to find mass of gold we first calculate the amount of heat required to heat the unit mass of gold to specified temperature:

Mass Specific Heat = C * ΔT

Mass Specific Heat = (0.130 J/g.°C)(11.6 °C)

Mass Specific Heat = 1.508 J/g

Now, for the mass of gold (m):

mass of gold = Heat/Mass Specific Heat

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mass of gold = 310.34 g

6 0

4 years ago

How can the shape of a molecule determine its polarity.

Natasha_Volkova [10]

Answer:

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Explanation:

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3 years ago

Ferris & Mona used the ORP sensor to titrate a ferrous ammonium sulfate solution, (NH4)2Fe(SO4)2 with KMnO4 titrant.

DIA [1.3K]

Answer:

The correct option is: A. 0.168 M

Explanation:

Chemical reaction involved:

5 Fe²⁺ (aq) + MnO₄⁻ (aq) + 8 H⁺ (aq) → 5 Fe³⁺ (aq) + Mn²⁺ (aq) + 4 H₂O

Given: For MnO₄⁻ solution-

Number of moles: n₁ = 1, Volume: V₁ = 20.2 mL, Concentration: M₁ = 0.0250 M;

For Fe²⁺ solution:

Number of moles: n₂ = 5, Volume: V₂ = 15 mL, Concentration: M₂ = ?M

To find out the concentration of Fe²⁺ solution (M₂), we use the equation:

$\frac{M_{1}\times V_{1}}{n_{1}} = \frac{M_{2}\times V_{2}}{n_{2}}$

$\frac{0.0250 M\times 20.2 mL}{1} = \frac{M_{2}\times 15 mL}{5}$

$0.505 = M_{2}\times 3$

$M_{2} = \frac{0.505}{3} = 0.168M$

Therefore, the concentration or molarity of Fe²⁺ solution: M₂ = 0.168 M

8 0

4 years ago