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4 years ago

What mass of helium is in a 2.00L ballon at STP

Chemistry

1 answer:

MAXImum [283]4 years ago

6 0

Answer:

0.357 g He

Explanation:

1 mol of gas at STP = 22.4 L

2.00 L * 1 mol/22.4 L = 0.08929 mol He

M(He) = 4.00 g/mol

0.08929 mol He * 4.00 g/ 1 mol He = 0.357 g He

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klemol [59]

The first one would be it

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4 years ago

The change in velocity over a specific amount of time Includes speeding up. slowing down or changing direction. This is known as

Nana76 [90]

Answer:

Acceleration

Explanation:

Acceleration = $\frac{velocity}{time}$

3 0

3 years ago

What is the percentage error of length measurement of 0.229cm if the correct value is 0.225cm

Mars2501 [29]

Percent error is the difference between the measured and known value, divided by the known value, multiplied by 100%.

So first, we take our measured value, .299 cm, minus our known value, .225 cm.

.299 cm - .225 cm=.004 cm

Next, we divide that by our known value

$\frac{.004}{.225}=.0177777778$

Finally, multiply your answer by 100

.0177777778 x 100= 1.77777778 %

Round to three significant figures, and you're done.

=1.78 % error

5 0

4 years ago

Read 2 more answers

What color does copper produce when it reacts to chlorine

kiruha [24]

The color it produces is Bright green.

6 0

3 years ago

If the initial temperature of a movable cylinder was 50 degrees Celsius

slega [8]

Answer:

8.45 L

Explanation:

From the question given above, the following data were obtained:

Initial temperature (T₁) = 50 °C

Initial pressure (P₁) = 2 atm

Initial volume (V₁) = 5 L

Final temperature (T₂) = 0 °C

Final pressure (P₂) = 1 atm

Final volume (V₂) =?

Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T₁) = 50 °C

Initial temperature (T₁) = 50 °C + 273

Initial temperature (T₁) = 323 K

Final temperature (T₂) = 0 °C

Final temperature (T₂) = 0 °C + 273

Final temperature (T₂) = 273 K

Finally, we shall determine the new volume. This can be obtained as follow:

Initial temperature (T₁) = 323 K

Initial pressure (P₁) = 2 atm

Initial volume (V₁) = 5 L

Final temperature (T₂) = 273 k

Final pressure (P₂) = 1 atm

Final volume (V₂) =?

P₁V₁ / T₁ = P₂V₂ / T₂

2 × 5 / 323 = 1 × V₂ / 273

10 / 323 = V₂ / 273

Cross multiply

323 × V₂ = 10 × 273

323 × V₂ = 2730

Divide both side by 323

V₂ = 2730 / 323

V₂ = 8.45 L

Thus, the new volume is 8.45 L

5 0

3 years ago