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2 years ago

Which is an example of ionization?

Chemistry

1 answer:

strojnjashka [21]2 years ago

8 0

Answer: SO₂ + H₂O → HSO₃ ⁻ + H⁺

Justification:

1) Ionization means formation of ions.

2) Ions are species that are not neutral, they are charged, in virtue of having less or more electrons than protons.

3) Ionization may happen in different environments.

4) Ionic compunds, like Mg(OH)₂ dissociate into ions (ionize) in water. That is the example shown in the fourth option:

Mg(OH)₂ → Mg ²⁺ + 2OH⁻

5) How much a ionic compound dissociates in water (ionize) depends on the Ksp (product solubility constant) which measures the concentrations of the ions that can be in the solution.

6) The Ksp for Mg(OH)₂ is very low, meaning that it will slightly ionize.

7) SO₂ + H₂O forms H₂SO₄, which is a strong acid, meaning that it will ionize fully in water, into the ions HSO₃ ⁻ and H⁺, so the third option is a good example of ionization.

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How many grams of sodium acetate ( molar mass = 83.06 g/mol ) must be added to 1.00 Liter of a 0.200 M acetic acid solution to m

Pie

<u>Answer:</u> The mass of sodium acetate that must be added is 30.23 grams

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of acetic acid solution = 0.200 M

Volume of solution = 1 L

Putting values in above equation, we get:

$0.200M=\frac{\text{Moles of acetic acid}}{1L}\\\\\text{Moles of acetic acid}=(0.200mol/L\times 1L)=0.200mol$

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

$pH=pK_a+\log(\frac{[\text{salt}]}{[\text{acid}]})$

$pH=pK_a+\log(\frac{[CH_3COONa]}{[CH_3COOH]})$

We are given:

$pK_a$ = negative logarithm of acid dissociation constant of acetic acid = 4.74

$[CH_3COONa]=?mol$

$[CH_3COOH]=0.200mol$

pH = 5.00

Putting values in above equation, we get:

$5=4.74+\log(\frac{[CH_3COONa]}{0.200})$

$[CH_3COONa]=0.364mol$

To calculate the mass of sodium acetate for given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of sodium acetate = 83.06 g/mol

Moles of sodium acetate = 0.364 moles

Putting values in above equation, we get:

$0.364mol=\frac{\text{Mass of sodium acetate}}{83.06g/mol}\\\\\text{Mass of sodium acetate}=(0.364mol\times 83.06g/mol)=30.23g$

Hence, the mass of sodium acetate that must be added is 30.23 grams

7 0

3 years ago

How many carbon atoms are there on the reactant side of this equation?

amid [387]

Its obviously D like what are you stupid lol jk don’t take it to heart kid

4 0

3 years ago

NO FILES

MrMuchimi

Answer:

the general equation is: A + X → AX. Where a single compound on the reactant side breaks down into two or more products during a chemical change. The general equation is AX → A + X.

Explanation:

6 0

3 years ago

A balloon is filled to a volume of 1.50 L with 3.00 mol of gas at 25 C. with pressure and temperature held constant, what will b

bixtya [17]

Answer:

3.2L

Explanation:

PV=nRT

since pressure and temperature are held constant we have V=nR

R is a constant also,

Thus; $\frac{v1}{n1}=\frac{v2}{n2}$